Question

当我运行代码时，我没有收到任何错误，但是我要显示的数据没有显示，只是空白..有人可以告诉我我在做什么错吗？

我的控制器：

public function openingPage($id) {

      $this->getGames();
      $games = $this->getGames();

      return view('caseopener')->with('games',$games);

    }

private function getGames() {
      $games = array();
      foreach ($this->data->items as $item) {
          $game = new Game($item);
          $games[] = array(
                'id' => $game['id'],
                'name' => $game['name'],
                'price' => $game['price'],
                'image' => $game['image'],
            );

      }

      return $games;
  }

“ getGames函数”中使用的“ 游戏”模型：

class Game extends Model
{
  private $id;
  public $data;

  public function __construct($id) {
       parent::__construct();
       $this->id = $id;
       $this->data = $this->getData();
   }

   private function getData() {

       $game = DB::table('products')->where('id', 1)->first();

       if(empty($game)) return array();

       return $game;
   }
}

视图：

@foreach ($games as $game)

    <div class="gold">$ {{ $game['price'] }}</div>

@endforeach

Answer 1

我认为您太过复杂了。您可以像这样简化流程：

鉴于您提供的代码，似乎您正在'products'模型中使用自定义表名称（Game）。所以我们先解决这个问题：

Game.php

class Game extends Model
{
    protected $table = 'products'; //
}

现在，似乎您正在搜索Game个ID（$this->data->items）的数组。如果是这样，您可以使用Eloquent进行查询，特别是whereIn()方法：

YourController.php

public function openingPage($id)
{
    $games = Game::whereIn('id', $this->data->items)->get();

    return view('caseopener')->with('games', $games);
}

（可选）如果您要确保只返回每个id /产品的name，price，image和Game，则可以用API Resources格式化响应：

php artisan make:resource GameResource

然后在您新创建的班级中：

app / Http / Resources / GameResource.php

namespace App\Http\Resources;

use Illuminate\Http\Resources\Json\JsonResource;

class GameResource extends JsonResource
{
    /**
     * Transform the resource into an array.
     *
     * @param  \Illuminate\Http\Request  $request
     * @return array
     */
    public function toArray($request)
    {
        return [
            'id' => $this->id,
            'name' => $this->name,
            'price' => $this->price,
            'image' => $this->image,
        ];
    }
}

所以现在只需更新您的控制器即可：

YourController.php

use App\Http\Resources\GameResource;

public function openingPage($id)
{
    $games = Game::whereIn('id', $this->data->items)->get();

    return view('caseopener')->with('games', GameResource::collection($games));
} //                                         ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

Laravel从数据库数组获取数据不起作用

1 个答案: