你好,我是Laravel的新手,我陷入了Laravel雄辩的复杂查询中
这是我的邮件表格结构
---|-----------|-------------|--------
ID | sender_id | receiver_id | message
---|-----------|-------------|--------
1 | 1 | 2 | Hello
2 | 1 | 2 | Hey hello reply
3 | 2 | 1 | Good
4 | 3 | 2 | Hey GOOD Morning
5 | 3 | 2 | good night
我想从消息表中检索最近的聊天记录,无论是用户还是发件人或接收者,我都想使用groupBy使用多列检索,并且只显示最近一条消息。
喜欢用户2(发送者或接收者)
-----------|-------------|---------------
sender_id | receiver_id | message
-----------|-------------|---------------
2 | 1 | Good
3 | 2 | good night
这是我雄辩的查询
$user = auth()->user(); //User_id 2 based on logged in user either sender or reciever
Message::where('user_id', $user->id)
->orWhere('receiver_id', $user->id)
->select('user_id','receiver_id')
->groupBy('user_id','receiver_id')
->get();
结果
all: [
App\Models\Message {
user_id: 1,
receiver_id: 2,
}, // don't want this record
App\Models\Message {
user_id: 2,
receiver_id: 1,
},
App\Models\Message {
user_id: 3,
receiver_id: 2,
},
],
如果我尝试使用Latest()方法,则表明表中存在错误时间戳记
Illuminate / Database / QueryException,消息为'SQLSTATE [42000]:
语法错误或访问冲突:1055 ORDER BY子句的表达式#1不在GROUP BY子句中,并且包含未聚合的列
我不想在mysql_strict
中更新config/database.php
模式
它不能正常工作,任何人都可以帮我或任何好的建议或想法
任何帮助都会感激
答案 0 :(得分:1)
您能找出如何在Laravel中表达这一点吗?
**Schema (MySQL v5.7)**
CREATE TABLE my_table
(ID SERIAL PRIMARY KEY
,sender_id INT NOT NULL
,receiver_id INT NOT NULL
,message VARCHAR(50) NOT NULL
);
INSERT INTO my_table VALUES
(1,1,2,'Hello'),
(2,1,2,'Hey hello reply'),
(3,2,1,'Good'),
(4,3,2,'Hey GOOD Morning'),
(5,3,2,'good night');
---
**Query #1**
SELECT a.*
FROM my_table a
JOIN
( SELECT MAX(id) id
FROM my_table
WHERE 2 IN(sender_id,receiver_id)
GROUP
BY LEAST(sender_id,receiver_id)
, GREATEST(sender_id,receiver_id)
) b
ON b.id = a.id;
| ID | sender_id | receiver_id | message |
| --- | --------- | ----------- | ---------- |
| 3 | 2 | 1 | Good |
| 5 | 3 | 2 | good night |
---