Question

我有一个txt文件，其中某些列并未出现在每一行中，但这会导致问题，在它们出现的行中，它们弄乱了我的列的顺序：

35 = d | 5799 = 00000000 | 980 = A | 779 = 20190721173046000465 | 1180 = 310 | 1300 = 64 | 462 = 5 | 207 = XCME | 1151 = ES | 6937 = ES | 55 = ESM0 | 48 = 163235 | 22 = 8 | 167 = FUT | 461 = FFIXSX | 200 = 202006 | 15 = USD | 1142 = F | 562 = 1 | 1140 = 3000 | 969 = 25.000000000 | 9787 = 0.010000000 | 996 = IPNT | 1147 = 50.000000000 | 1150 = 302775.000000000 | 731 = 00000110 | 5796 = 20190724 | 1149 = 315600.000000000 | 1148 = 285500.000000000 | 1143 = 600.000000000 | 1146 = 12.500000000 | 9779 = N | 864 = 2 | 865 = 5 | 1145 = 20190315133000000000 | 865 = 7 | 1145 = 20200619133000000000 | 1141 = 1 | 1022 = GBX | 264 = 10 | 870 = 1 | 871 = 24 | 872 = 00000000000001000010000000001111 | 1234 = 0 | 5791 = 279 | 5792 = 10121 |

35 = d | 5799 = 00000000 | 980 = A | 779 = 20190721173046000465 | 1180 = 310 | 1300 = 64 | 462 = 5 | 207 = XCME | 1151 = ES | 6937 = ES | 55 = ESU9 | 48 = 191262 | 22 = 8 | 167 = FUT | 461 = FFIXSX | 200 = 201909 | 15 = USD | 1142 = F | 562 = 1 | 1140 = 3000 | 969 = 25.000000000 | 9787 = 0.010000000 | 996 = IPNT | 1147 = 50.000000000 | 1150 = 302150.000000000 | 731 = 00000110 | 5796 = 20190724 | 1149 = 315700.000000000 | 1148 = 285600.000000000 | 1143 = 600.000000000 | 1146 = 12.500000000 | 9779 = N | 864 = 2 | 865 = 5 | 1145 = 20180615133000000000 | 865 = 7 | 1145 = 20190920133000000000 | 1141 = 1 | 1022 = GBX | 264 = 10 | 870 = 1 | 871 = 24 | 872 = 00000000000001000010000000001111 | 1234 = 0 | 5791 = 250519 | 5792 = 452402 |

35 = d | 5799 = 00000000 | 980 = A | 779 = 20190721173046000465 | 1180 = 310 | 1300 = 64 | 462 = 5 | 207 = XCME | 1151 = $ E | 6937 = 0ES | 55 = 0ESQ9 | 48 = 229588 | 22 = 8 | 167 = FUT | 461 = FFIXSX | 200 = 201908 | 15 = USD | 1142 = F | 562 = 1 | 1140 = 3000 | 969 = 25.000000000 | 9787 = 0.010000000 | 996 = IPNT | 1147 = 50.000000000 | 1150 = 25.000000000 | 731 = 00000011 | 5796 = 20190607 | 1143 = 0.000000000 | 1146 = 12.500000000 | 9779 = N | 864 = 2 | 865 = 5 | 1145 = 20190621133000000000 | 865 = 7 | 1145 = 20190816133000000000 | 1141 = 1 | 1022 = GBX | 264 = 10 | 870 = 1 | 871 = 24 | 872 = 00000000000001000010000000001111 | 1234 = 0 |

35 = d | 5799 = 00000000 | 980 = A | 779 = 20190721173114000729 | 1180 = 441 | 1300 = 56 | 462 = 16 | 207 = DUMX | 1151 = 1O | 6937 = OQE | 55 = OQEH4 C6100 | 48 = 1546 | 22 = 8 | 167 = OOF | 461 = OCEFPS | 201 = 1 | 200 = 202403 | 15 = USD | 202 = 6100.000000000 | 947 = USD | 9850 = 0.100000000 | 1142 = F | 562 = 1 | 1140 = 999 | 969 = 1.000000000 | 1146 = 10.000000000 | 9787 = 0.010000000 | 996 = BBL | 1147 = 1000.000000000 | 731 = 00000001 | 1148 = 0.100000000 | 9779 = N | 5796 = 20190718 | 864 = 2 | 865 = 5 | 1145 = 20181031213000000000 | 865 = 7 | 1145 = 20240126193000000000 | 1141 = 1 | 1022 = GBX | 264 = 3 | 870 = 1 | 871 = 24 | 872 = 00000000000001000000000100000101 | 1234 = 1 | 1093 = 4 | 1231 = 1.0000 | 711 = 1 | 309 = 211120 | 305 = 8 | 311 = OQDH4 | 1647 = 0 |

35 = d | 5799 = 00000000 | 980 = A | 779 = 20190721173115000229 | 1180 = 441 | 1300 = 56 | 462 = 16 | 207 = DUMX | 1151 = 1O | 6937 = OQE | 55 = OQEM4 C5700 | 48 = 2053 | 22 = 8 | 167 = OOF | 461 = OCEFPS | 201 = 1 | 200 = 202406 | 15 = USD | 202 = 5700.000000000 | 947 = USD | 9850 = 0.100000000 | 1142 = F | 562 = 1 | 1140 = 999 | 969 = 1.000000000 | 1146 = 10.000000000 | 9787 = 0.010000000 | 996 = BBL | 1147 = 1000.000000000 | 731 = 00000001 | 1148 = 0.100000000 | 9779 = N | 5796 = 20190718 | 864 = 2 | 865 = 5 | 1145 = 20181031213000000000 | 865 = 7 | 1145 = 20240425183000000000 | 1141 = 1 | 1022 = GBX | 264 = 3 | 870 = 1 | 871 = 24 | 872 = 00000000000001000000000100000101 | 1234 = 1 | 1093 = 4 | 1231 = 1.0000 | 711 = 1 | 309 = 329748 | 305 = 8 | 311 = OQDM4 | 1647 = 0 |

例如，在前三行中总是出现461=…，然后是200=…，而从461=…和200=…之间的第四行开始是201=…

现在，我想到了以某种方式将以后出现的每一列（第一行中不存在的那一列）移动到该行的末尾，从而使其成为最后一列，但是我不知道该如何精确地执行此操作。这是我尝试过的：

 private static void ladeDatei(String datName) { 

        File file = new File(datName); 

        if (!file.canRead() || !file.isFile()) 
            System.exit(0); 

            BufferedReader in = null; 
        try { 
            in = new BufferedReader(new FileReader(datName)); 
            String row = null;
                String row2 = null; 
            while ((row = in.readLine()) != null) { 
                System.out.println("Gelesene Zeile: " + row); 

                 while(row.contains("|")) {

                    row2 = row.substring(row.indexOf("|") + 1);
                    row=row2;
                    row2 = row.substring(0, row.indexOf("=") + 1);
                    row2 = row2.replace("=", "");
                    if(!numbers.contains(row2)) {
                        numbers.add(row2);
                    }
                    System.out.println(row);
                    //System.out.println(row2);
                }             

            } 
        } catch (IOException e) { 
            e.printStackTrace(); 
        } finally { 
            if (in != null) 
                try { 
                    in.close(); 
                } catch (IOException e) { 
                } 
        } 
    }

我考虑过用|分隔每一行并将它们保存在textArr列表中，但是我不知道哪些行属于同一行。我的主要问题是，我不知道一种检查该列是否存在于较早行中以及如何将其移至该行末尾的好方法。

编辑：现在我将每个新条目保存在数字arraylist中（请参见上面的代码，在我的编辑中），但是现在我被卡住了，因为我不知道如何将它们以及所有在它们之后的那些都移到最后每行。

Answer 1

那真是一件难事。我要做的是：
（1）在|
处分割行（2）制作一个List，在|和=之间附加数字（在末尾添加每个新数字）
（3）制作一个Map，其中线部分作为键映射到（2）中的数字
（4）再进行Map，其中线部分的最大列值映射到（2）中的数字
（5）从（2）joinig关联的行部分通读列表，其中|填充到最大列值（如果没有用于特定编号的线部分，则也必须进行填充）
只要有可能，我都希望在html表中构造线条部分。
列顺序的更改不会解决更大或更小的列的问题。

更改txt文件中列的顺序

1 个答案: