Question

我需要打开许多json文件并将它们写入一个csv文件，我编写了一个代码来读取一个文件，但是当我想将所有文件附加在一起时，我收到了回溯。

我的代码是

path_to_json = r'\path'
json_files = [pos_json for pos_json in os.listdir(path_to_json) if pos_json.endswith('.json')]
json_text_list = []
for index, js in enumerate(json_files):
    with open(os.path.join(path_to_json, js), encoding="utf8") as json_file:
        json_text_list.append(json.load(json_file))
        json_text = json.load(json_file)

错误：

File "C:\Users\and\Desktop\t.py", line 18, in <module>
    json_text = json.load(json_file)
  File "C:\Users\and\AppData\Local\Programs\Python\Python37-32\lib\json\__init__.py", line 296, in load
    parse_constant=parse_constant, object_pairs_hook=object_pairs_hook, **kw)
  File "C:\Users\and\AppData\Local\Programs\Python\Python37-32\lib\json\__init__.py", line 348, in loads
    return _default_decoder.decode(s)
  File "C:\Users\and\AppData\Local\Programs\Python\Python37-32\lib\json\decoder.py", line 337, in decode
    obj, end = self.raw_decode(s, idx=_w(s, 0).end())
  File "C:\Users\and\AppData\Local\Programs\Python\Python37-32\lib\json\decoder.py", line 355, in raw_decode
    raise JSONDecodeError("Expecting value", s, err.value) from None
json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

Answer 1

您需要做的是在读取模式下打开文件，并在文件处理程序上调用.read()方法，以将内容作为可被json解析的字符串来获取。

这就是为什么我们使用json.loads()

这是解决方案-

import os
import json

path_to_json = r'\path'
json_files = [pos_json for pos_json in os.listdir(path_to_json) if pos_json.endswith('.json')] 
json_text_list = [] 
for index, js in enumerate(json_files): 
    with open(os.path.join(path_to_json, js), 'r') as json_file:
        json_data = json.loads(json_file.read())
        json_text_list.append(json_data)

json.decoder.JSONDecodeError：期望值：第1行第1列（字符0）object_pairs_hook = object_pairs_hook，** kw）

1 个答案: