Question

我的目标是编写一个python脚本，该脚本枚举来自/ etc / passwd和/ etc / group（或它们的用户）的系统用户和组。网络数据库等效项）。为每个用户打印用户的UID以及该用户所属的组。
标记具有多个用户名的UID。标记具有多个组名的GID 与他们相关联。我有两个单独的脚本可以实现这一目标，但是如何将它们组合为一个？

#!/usr/bin/env python

from collections import defaultdict

# Initialize dictionary of user ids
uids = defaultdict(list)

# loop through password file, building dictionary of uid:[list of   usernames]
with open("/etc/passwd") as passwd_file:
  for line in passwd_file: 
    line_array = line.split(":")
    uids[line_array[2]].append(line_array[0])

# loop though dictionary. 
# If duplicate usernames for uid found, print on standard out

for uid in uids:
  if len(uids[uid]) > 1:
    print ( uid + ": " + " ".join(uids[uid]))
#!/usr/bin/env python

from collections import defaultdict

# Initialize dictionary of group ids
gids = defaultdict(list)

# loop through password file, building dictionary of gid:[list of groups]
with open("/etc/group") as group_file:
  for line in group_file: 
    line_array = line.split(":")
    gids[line_array[2]].append(line_array[0])

# loop though dictionary. 
# If duplicate group for gid found, print on standard out

for gid in gids:
  if len(gids[gid]) > 1:
    print ( gid + ": " + " ".join(gids[gid]))

如何结合两个脚本？

0 个答案: