我有一个父类Company
,其中有Employee
个对象的列表。我需要创建一个Parent
类的流,其中有一个Employee
并带有提到的电话号码。
Company cmp1 = new Company();
cmp1.setName("oracle");
Company cmp2 = new Company();
cmp1.setName("Google");
Employee emp1 = new Employee();
emp1.setName("David");
emp1.setPhone("900");
Employee emp2 = new Employee();
emp2.setName("George");
emp2.setPhone("800");
Employee emp4 = new Employee();
emp4.setName("BOB");
emp4.setPhone("300");
Employee emp5 = new Employee();
emp5.setName("taylor");
emp5.setPhone("900");
List<Employee> cmp1EmpList1 = new ArrayList<Employee>();
cmp1EmpList1.add(emp1);
cmp1EmpList1.add(emp2);
cmp1.setEmployees(cmp1EmpList1);
List<Employee> cmp1EmpList2 = new ArrayList<Employee>();
cmp1EmpList2.add(emp4);
cmp1EmpList2.add(emp5);
cmp2.setEmployees(cmp1EmpList2);
List<Company> companies = Arrays.asList(cmp1, cmp2);
要检索流,我尝试添加以下代码
List<Company> companiesWithEmployeesphone800 = companies.stream()
.filter(loc -> loc.getEmployees()
.stream()
.flatMap(locnew -> locnew.getPhone()
.equalsIgnoreCase("800"))
)
.collect(Collectors.toList());
但是收到了不兼容的类型。
答案 0 :(得分:2)
将anyMatch
用作谓词,而不用flatMap
作为谓词:
List<Company> companiesWithEmployeesphone800 =
companies.stream()
.filter(loc -> loc.getEmployees().stream()
.anyMatch(locnew -> locnew.getPhone().equalsIgnoreCase("800")))
.collect(Collectors.toList());