我有一个简单的for循环,可以迭代各种日期的列表。对于列表中的每个项目,我仅采用前10个字符来排除时区。但是,当我将对象传递给模板时,仅返回所有值的列表中的第一个值。
views.py
for opportunity in opportunities:
temp = opportunity['expectedCloseDate']
time = temp[:10]
context { 'time': time }
return render(request, 'website', context)
template.html
<div class="control is-inline-flex">
<input class="input" name="close_date" id="close_date" type="date" value="{{ time }}" disabled>
</div>
答案 0 :(得分:2)
您可以构建times
的列表:
times = [opportunity['expectedCloseDate'][:10] for opportunity in opportunities]
return render(request, 'website', {'times': times})
,然后在模板中对其进行迭代:
<div class="control is-inline-flex">
{% for time in times %}
<input class="input" name="close_date" id="close_date" type="date" value="{{ time }}" disabled>
{% endfor %}
</div>
话虽如此,看来您正在手动构建表单。通常最好在这里使用Django的Form
object [Django-doc]。
如果要同时在两个列表上循环,可以使用zip
,例如:
times = [opportunity['expectedCloseDate'][:10] for opportunity in opportunities]
opps_times = zip(opportunities, times)
return render(request, 'website', {'opps_times': opps_times})
并使用以下内容呈现:
{% for opportunity, time in opps_times %}
<!-- ... -->
{% endfor %}
答案 1 :(得分:1)
您总是在每次迭代中都覆盖时间。尝试类似
time = []
for opportunity in opportunities:
temp = opportunity['expectedCloseDate']
time.append(temp[:10])
context = { 'time': time }
return render(request, 'website', context)