Question

我确实有一个列表(run* [a d q] (everyg #(conso a d %) [q])) => ([_0 _1 (_0 . _1)])和一个翻译列表：

everyg

Culture

当前代码public class Translation { public string key { get; set; } public string value { get; set; } public string cultureId { get; set; } }返回：

public async Task<IActionResult> ReactGetResources(string module = "shared")
{
    string[] Languages = { "en-US", "fr-FR", "it-IT", "es-ES" };

    List<Translation> Translation = new List<Translation>();
    Translation.Add(new Translation { key = "hello", value = "Hello", cultureId = "en-US" });
    Translation.Add(new Translation { key = "hello", value = "Bonjour", cultureId = "fr-FR" });
    Translation.Add(new Translation { key = "hello", value = "Buongiorno", cultureId = "it-IT" });
    Translation.Add(new Translation { key = "goodbye", value = "Good Bye", cultureId = "en-US" });
    Translation.Add(new Translation { key = "goodbye", value = "Au revoir", cultureId = "fr-FR" });
    Translation.Add(new Translation { key = "goodbye", value = "adiós", cultureId = "es-ES" });

    Dictionary<string, List<string>> query = Translation
        .OrderBy(o => o.cultureId)
        .GroupBy(o => o.key)
        .ToDictionary(g => g.Key, g => g.Select(x => x.value).ToList());

    return Json(query);
}

但是我希望为缺失的翻译添加IActionResult值： { "hello": [ "Hello", //en "Bonjour", //fr "Buongiorno" //it ], "goodbye": [ "Good Bye", //en "Au revoir", //fr "Adiós", //es ] }

Null

可以仅使用{ "en-US", "fr-FR", "it-IT", "es-ES" }吗？或者，也许我应该在字典中添加{ "hello": [ "Hello", //en "Bonjour", //en "Buongiorno", //it null //es ], "goodbye": [ "Good Bye", //en "Au revoir", //fr null, //it "Adiós" //es ] }并重新填充值？

Answer 1

您为什么首先希望如此？您实际上是在告诉它只选择value。 cultureId和您的Languages数组都没有被提及或利用，那么为什么您甚至希望它们发挥某种作用呢？

您需要类似以下GroupBy的内容：

.GroupBy(g => g.key, (key, items) => Languages.Select(lang => items.FirstOrDefault(i => i.cultureId == lang)?.value))

Answer 2

您可以加入您的语言列表，类似这样（尚未试用）

Dictionary<string, List<string>> query = Translation
    .GroupBy(o => o.key)
    .ToDictionary(g => g.Key, g => 
        Languages.Select(l => g.FirstOrDefault(x => x.cultureId == l)?.value));

说明：

我们将组映射到语言列表中。对于每种语言，如果组中具有与cultureId匹配的元素，请使用该值，或者使用null。

（目前无法测试，如有任何错误，请事先谅解）

Answer 3

您尝试在linq中执行"left join"，这可以使用Join和DefaultIfEmpty运算符进行。只要我知道，就只能使用声明性语法：

libsass-dev

我同意这不是最易读的查询，也许以程序方式进行查询可能会更简单。

Answer 4

使用以下代码

Dictionary<string, List<string>> query = Translation
            .OrderBy(o => o.cultureId)
            .GroupBy(o => o.key)
            .ToDictionary(g => g.Key, g => Languages.GroupJoin(g.Select(x => x), f => f, s => s.cultureId, (f, s) => s).SelectMany(x => x.DefaultIfEmpty(),(x, y) => y != null? y.value :null).ToList());

并更正最后的翻译

Translation.Add（新翻译{键=“再见”，值=“adiós”， cultureId =“ es-ES”}）;

Translation.Add（新翻译{键=“再见”，值=“adiós”，文化ID =“ es-US”}）;

Linq to具有空值的Dictionary <string，List <string >>

4 个答案: