Question

我需要在Filedialog tkinter中获取选定的路径，但我不知道如何做，因为在图形窗口中直接选择路径时，保存是因为无法提取路径将其存储在变量中

from tkinter import filedialog
open_f = filedialog.asksaveasfile(mode='w', defaultextension='.txt')
path_f =

如您所见，我需要将在open_f中获得的路由存储在变量path_f ..中，但是open_f仅返回_io.textiowrapper ..

如何在文件对话框中获取路径？

Answer 1

如果实际上只需要一个文件名，请使用tkinter.filedialog.asksaveasfilename()：

from tkinter import filedialog

filepath = filedialog.asksaveasfilename()
print(filepath)
# '/home/norok2/.xsession-errors'

Answer 2

您应该使用对象的name方法。如下所示：

open_f = tkFileDialog.asksaveasfile(mode='w', defaultextension='.txt')
path_f = your_file.name

Answer 3

尝试：

def open():
    open_f = filedialog.asksaveasfile(mode='w', defaultextension='.txt')
    path_f = open_f.name
    # You Can Do Anything Here(e.g. print(path_f))

完整代码：

from tkinter import filedialog

def open():
    open_f = filedialog.asksaveasfile(mode='w', defaultextension='.txt')
    path_f = open_f.name
    print(path_f)
# '/home/norok2/.xsession-errors'

# You can run it by typing:
open()

Answer 4

out = filedialog.asksaveasfile(mode='w', defaultextension=".xlsx")
out.close()

restr = str(out)
    
RegexPrep = restr.replace("'w'", '')
outRegex = re.findall(r"'(.*?)'", RegexPrep)
ToExcelRegex = str(outRegex)
    
MorePrep = ToExcelRegex.replace("[",'')
MorePrep = MorePrep.replace("]",'')
MorePrep = MorePrep.replace("'",'')
MorePrep = MorePrep.replace(", cp1252",'')
Final = MorePrep.strip()

一种更简单的方法：

open_f = tkFileDialog.asksaveasfile(mode='w', defaultextension='.txt')
path_f = your_file.name

如何使用Tkinter文件对话框获取路径？

4 个答案: