Question

data = [
    ['Video A','500'],
    ['Video B','300'],
    ['Video C','1000']
]

result = 0

for index in data:
    title = index[0]
    views = index[1]

    if title == 'Video' :
         result += views

print(result)

当我运行print时，我总是得到0。答案应该是1800。问题是没有错误，而且我找不到我犯错的部分。

Answer 1

好像您想检查标题以 "Video"开头。

此外，您的视图是字符串，需要转换为整数。

尝试一下：

data = [
    ['Video A', '500'],
    ['Video B', '300'],
    ['Video C', '1000']
]

result = 0

for index in data:
    title = index[0]
    views = index[1]

    if title.startswith('Video'):
        result += int(views)

print(result)

Answer 2

正确的代码：

data = [
    ['Video A','500'],
    ['Video B','300'],
    ['Video C','1000']
]

result = 0

for index in data:
    title = index[0]
    views = index[1]

    #you can use
    #if title[:len("Video")] == 'Video':
    #or
    #if title.startswith('Video'):
         result += int(views)

print(result)

Answer 3

您也可以使用split：

data =
    ['Video A','500'],
    ['Video B','300'],
    ['Video C','1000']
]

result = 0

for index in data:
    title = index[0]
    views = index[1]

    if title.split(' ',1)[0] == 'Video' :
         result += int(views)

print(result)

它可以确保'Video'后面有一个空格，并可以访问名称的其余部分：

v = "Video A and B"
l = v.split(" ",1)
l[0] # 'Video'
l[1] # 'A and B'

我有一个硬件问题，因为我能够打印，所以我找不到错误。有人可以协助我吗？

3 个答案: