Question

请考虑以下两个列表

list1 = ["tom","sam","ram","omlet"]
list2 = ["com","dome","mom","omega"]

使用以下代码，每种情况下的输出均为True：

for a,b in zip(list1,list2):
    cond = "om" in (a and b)
    print(cond)

输出：

True
True
True
True

由于list1和list2中对应的元素“ sam”和“ dome”只有“ dome”具有“ om”，因此它应该满足条件吗？，但是输出为True。

如何检查条件，如果子字符串“ om”与列表的相应元素中的两个字符串完全匹配完全匹配。

预期输出：

True
False
False
True

Answer 1

您有：

list1 = ["tom","sam","ram","omlet"]
list2 = ["com","dome","mom","omega"]

for a,b in zip(list1,list2):
    cond = ("om" in a) and ('om' in b)
    print(cond)

输出：

True
False
False
True

Answer 2

您正在使用in (a and b)做您不想要的事情-您仅在后者中检查存在性，因为（a和b）给出b。您需要：

cond = "om" in a and "om" in b

Answer 3

尝试一下：

    list1 = ["tom","sam","ram","omlet"]
    list2 = ["com","dome","mom","omega"]
    for i in range(len(list1)):
        cond=("om" in list1[i]) and ("om" in list2[i])
        print(cond)

它将打印您的预期输出

True
False
False
True

如何检查两个或多个字符串中的确切子字符串

3 个答案: