如何从事件处理程序中的对象中打印多个键?
这是我的代码的链接-https://codesandbox.io/s/suspicious-hamilton-erkqv
在行35上的我用对象“ x”调用事件处理程序ChangeName。我能够打印一个称为“名称”(x.name)的键 我该如何打印x对象的所有3个道具(名称,id,类型)?
试图将x转换为带有object.keys(x)的数组,但是当我循环遍历输出时,出现错误,提示无法使用map函数
const ChangeName = x => {
setvalue(x.name);
};
<div>{value}</div> // display the results
答案 0 :(得分:0)
您的值不是数组,它是一个对象,这就是为什么您不能使用map方法的原因,这就是它的工作原理:
import React, { useState, useEffect } from "react";
import ReactDOM from "react-dom";
function App() {
const [posts, setposts] = useState([]);
const [value, setvalue] = useState("");
useEffect(() => {
const posts = [
{
id: 1,
name: "Name 1",
type: "Type 1"
},
{
id: 2,
name: "Name 2",
type: "Type 2"
},
{
id: 3,
name: "Name 3",
type: "Type 3"
},
{
id: 4,
name: "Name 4",
type: "Type 4"
}
];
setposts(posts);
}, []);
const ChangeName = x => {
setvalue(x);
};
return (
<div>
<ul>
{posts.map(post => (
<li key={post.id}>
{post.name},{post.type}
<button onClick={() => ChangeName(post)}>More Info</button>
</li>
))}
</ul>
<div>
{value.name}
{value.id}
{value.type}
</div>
</div>
);
}
const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);
答案 1 :(得分:0)
运行代码:
import React, { useState, useEffect } from "react";
import ReactDOM from "react-dom";
function App() {
const [posts, setposts] = useState([]);
const [values, setvalue] = useState([]);
useEffect(() => {
const posts = [
{
id: 1,
name: "Name 1",
type: "Type 1"
},
{
id: 2,
name: "Name 2",
type: "Type 2"
},
{
id: 3,
name: "Name 3",
type: "Type 3"
},
{
id: 4,
name: "Name 4",
type: "Type 4"
}
];
setposts(posts);
}, []);
const ChangeName = x => {
console.log(Object.values(x));
Object.values(x).map(k => setvalue(k));
};
return (
<div>
<ul>
{posts.map(post => (
<li key={post.id}>
{post.name},{post.type}
<button onClick={ChangeName.bind(this, post)}>More Info</button>
</li>
))}
</ul>
<div>{values}</div>
</div>
);
}
const rootElement = document.getElementById("root");
ReactDOM.render(<App />, rootElement);
您需要将值设置为非值。