我正在尝试在本地设置AWS SAM，因此不必在每次更改代码时都进行部署。但是我很难从Secrets Manager中获取秘密。我使用sam init --runtime java
然后我在Secret Manager中创建了一个新机密，并更改了HelloWorldFunction中的代码以尝试检索该机密。
package helloworld;
import java.io.PrintWriter;
import java.io.StringWriter;
import java.util.Base64;
import java.util.HashMap;
import java.util.Map;
import com.amazonaws.services.lambda.runtime.Context;
import com.amazonaws.services.lambda.runtime.RequestHandler;
import com.amazonaws.services.secretsmanager.AWSSecretsManager;
import com.amazonaws.services.secretsmanager.AWSSecretsManagerClientBuilder;
import com.amazonaws.services.secretsmanager.model.*;
/**
* Handler for requests to Lambda function.
*/
public class App implements RequestHandler<Object, Object> {
public Object handleRequest(final Object input, final Context context) {
Map<String, String> headers = new HashMap<>();
headers.put("Content-Type", "application/json");
headers.put("X-Custom-Header", "application/json");
try {
String secretName = "testsecret";
String region = "us-west-2";
// Create a Secrets Manager client
AWSSecretsManager client = AWSSecretsManagerClientBuilder.standard()
.withRegion(region)
.build();
String secret, decodedBinarySecret;
GetSecretValueRequest getSecretValueRequest = new GetSecretValueRequest()
.withSecretId(secretName);
GetSecretValueResult getSecretValueResult = null;
try {
getSecretValueResult = client.getSecretValue(getSecretValueRequest);
} catch (DecryptionFailureException e) {
// Secrets Manager can't decrypt the protected secret text using the provided KMS key.
// Deal with the exception here, and/or rethrow at your discretion.
throw e;
} catch (InternalServiceErrorException e) {
// An error occurred on the server side.
// Deal with the exception here, and/or rethrow at your discretion.
throw e;
} catch (InvalidParameterException e) {
// You provided an invalid value for a parameter.
// Deal with the exception here, and/or rethrow at your discretion.
throw e;
} catch (InvalidRequestException e) {
// You provided a parameter value that is not valid for the current state of the resource.
// Deal with the exception here, and/or rethrow at your discretion.
throw e;
} catch (ResourceNotFoundException e) {
System.out.println(e.getMessage());
StringWriter outError = new StringWriter();
e.printStackTrace(new PrintWriter(outError));
System.out.println(outError.toString());
// We can't find the resource that you asked for.
// Deal with the exception here, and/or rethrow at your discretion.
throw e;
}
// Decrypts secret using the associated KMS CMK.
// Depending on whether the secret is a string or binary, one of these fields will be populated.
if (getSecretValueResult.getSecretString() != null) {
secret = getSecretValueResult.getSecretString();
return new GatewayResponse(secret, headers, 200);
}
else {
decodedBinarySecret = new String(Base64.getDecoder().decode(getSecretValueResult.getSecretBinary()).array());
return new GatewayResponse(decodedBinarySecret, headers, 200);
}
} catch (Exception e) {
return new GatewayResponse("{}", headers, 500);
}
}
}
当我运行sam local start-api并导航到http://127.0.0.1:3000/hello时，出现此错误：
Secrets Manager can’t find the specified secret. (Service: AWSSecretsManager; Status Code: 400; Error Code: ResourceNotFoundException; Request ID: 6881467f-d968-4f4e-ae60-7e3128124cc5)
com.amazonaws.services.secretsmanager.model.ResourceNotFoundException: Secrets Manager can’t find the specified secret. (Service: AWSSecretsManager; Status Code: 400; Error Code: ResourceNotFoundException; Request ID: 6881467f-d968-4f4e-ae60-7e3128124cc5)
at com.amazonaws.http.AmazonHttpClient$RequestExecutor.handleErrorResponse(AmazonHttpClient.java:1632)
at com.amazonaws.http.AmazonHttpClient$RequestExecutor.executeOneRequest(AmazonHttpClient.java:1304)
at com.amazonaws.http.AmazonHttpClient$RequestExecutor.executeHelper(AmazonHttpClient.java:1058)
at com.amazonaws.http.AmazonHttpClient$RequestExecutor.doExecute(AmazonHttpClient.java:743)
at com.amazonaws.http.AmazonHttpClient$RequestExecutor.executeWithTimer(AmazonHttpClient.java:717)
at com.amazonaws.http.AmazonHttpClient$RequestExecutor.execute(AmazonHttpClient.java:699)
at com.amazonaws.http.AmazonHttpClient$RequestExecutor.access$500(AmazonHttpClient.java:667)
at com.amazonaws.http.AmazonHttpClient$RequestExecutionBuilderImpl.execute(AmazonHttpClient.java:649)
at com.amazonaws.http.AmazonHttpClient.execute(AmazonHttpClient.java:513)
at com.amazonaws.services.secretsmanager.AWSSecretsManagerClient.doInvoke(AWSSecretsManagerClient.java:2024)
at com.amazonaws.services.secretsmanager.AWSSecretsManagerClient.invoke(AWSSecretsManagerClient.java:2000)
at com.amazonaws.services.secretsmanager.AWSSecretsManagerClient.executeGetSecretValue(AWSSecretsManagerClient.java:878)
at com.amazonaws.services.secretsmanager.AWSSecretsManagerClient.getSecretValue(AWSSecretsManagerClient.java:853)
at helloworld.App.handleRequest(App.java:53)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at lambdainternal.EventHandlerLoader$PojoMethodRequestHandler.handleRequest(EventHandlerLoader.java:259)
at lambdainternal.EventHandlerLoader$PojoHandlerAsStreamHandler.handleRequest(EventHandlerLoader.java:178)
at lambdainternal.EventHandlerLoader$2.call(EventHandlerLoader.java:888)
at lambdainternal.AWSLambda.startRuntime(AWSLambda.java:293)
at lambdainternal.AWSLambda.<clinit>(AWSLambda.java:64)
at java.lang.Class.forName0(Native Method)
at java.lang.Class.forName(Class.java:348)
at lambdainternal.LambdaRTEntry.main(LambdaRTEntry.java:114)
但是，获取机密管理器中给出的机密是相同的代码。无法从sam local连接到真实的AWS服务吗？我在DynamoDB上遇到了类似的问题，但是可以通过使用DynamoDB Local来使用它。
关于如何连接到真实机密管理器或以某种方式在本地伪造的任何建议？
答案 0 :(得分：0)
当您运行DynamoDB Local时，它实际上是在运行测试进程内的线程中（或作为本地进程，具体取决于您如何启动）运行模拟DDB服务器。不幸的是，Secrets Manager和其他AWS服务没有提供等效的测试解决方案。
但是，如果您返回ResourceNotFoundException，则似乎可以成功连接到Secrets Manager。与机密管理器的连接使用的帐户可能不同于您存储机密的帐户。您可以使用STS get caller identity调用来检查代码使用的凭据。