Question

我有两个表-订单表和子订单表

订单表

Order_Id |Customer |Status
--------------------------
101      Abc      1
102      xyz      1

子订单表

Sub_Order_Id | Order_Id    | Sub_order_status
---------------------------------------
10101          101         2
10102          101         2
10103          101         1
10201          102         1

如果所有子订单ID的状态均为= 2，我需要更新订单表的状态= 2

如果所有子订单状态均为2，则获取订单ID 101

Answer 1

您可以通过使用相关的子查询来尝试

        //This asks the user about how many numbers they are adding
        int equations = Convert.ToInt32(Console.ReadKey());

        if (equations == '1')
        {
            Console.WriteLine("That was an incorrect input, please close the application and try again.");
            Console.ReadKey();
        }

        //Start of code for adding 2 numbers
        if (equations == '2')
        {
            Console.WriteLine("What is the first number you would like to add?");
            int number = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("What is the second number you want to add?");
            int number2 = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("Press enter to calculate");
            Console.WriteLine(number + number2);
        }
        else
        {
            Console.WriteLine("That was an incorrect input, please close the application and try again.");
            Console.ReadKey();
        }
        //End of code for adding 2 numbers


        //Start of code for adding 3 numbers
        if (equations == '3')
        {
            Console.WriteLine("What is the first number you would like to add?");
            int number = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("What is the second number you want to add?");
            int number2 = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("What is the third number you would like to add?");
            int number3 = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("Press enter to calculate your equation");
            Console.WriteLine(number + number2 + number3);
        }
        else
        {
            Console.WriteLine("That was an incorrect input, please close the application and try again.");
            Console.ReadKey();
        }
        //End of code for adding 3 numbers


        //Start of code for adding 4 numbers
        if (equations == '4')
        {
            Console.WriteLine("What is the first number you would like to add?");
            int number = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("What is the second number you want to add?");
            int number2 = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("What is the third number you would like to add?");
            int number3 = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("What is the fourth number you would like to add?");
            int number4 = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("Press enter to calculate your equation");
            Console.WriteLine(number + number2 + number3 + number4);
        }
        else
        {
            Console.WriteLine("That was an incorrect input, please close the application and try again.");
            Console.ReadKey();
        }
        //End of code for adding 4 number


        // Start of code for adding 5 numbers
        if (equations == '5')
        {
            Console.WriteLine("What is the first number you would like to add?");
            int number = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("What is the second number you want to add?");
            int number2 = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("What is the third number you would like to add?");
            int number3 = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("What is the fourth number you would like to add?");
            int number4 = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("What is the fifth number you would like to add?");
            int number5 = Convert.ToInt32(Console.ReadLine());
            Console.WriteLine("Press enter to calculate your equation");
            Console.WriteLine(number + number2 + number3 + number4 + number5);
        }
        else
        {
            Console.WriteLine("That was an incorrect input, please close the application and try again.");
            Console.ReadKey();
        }
        //End of code for adding 5 numbers

Answer 2

您可以使用NOT EXISTS：

update o
set status = 2
from order o
where not exists (
  select 1 from suborder
  where order_id = o.order_id and sub_order_status <> 2
)

此语法将适用于SQL Server。
请参见demo。
如果您只需要选择订单：

select o.* 
from [order] o 
where not exists (
  select 1 from suborder
  where order_id = o.order_id and sub_order_status <> 2
)

Answer 3

以下查询应执行您想要的操作：

UPDATE o
    SET o.[Status] = 2
FROM
[order] o
WHERE o.Order_Id IN (
    SELECT Order_Id
    FROM [sub_order]
    GROUP BY Order_Id
    HAVING COUNT(*) = SUM(CASE WHEN Sub_order_status = 2 THEN 1 ELSE 0 END) )

用第二个表中的值更新第一个表中的列

3 个答案: