Question

默认情况下，我要在页面刷新/初始化时显示页面上的所有弹出窗口。我将引导程序用于弹出窗口。

jQuery：

$('[data-toggle="popover"]').popover();

HTML：

<button data-toggle="popover" title="" data-content="" data-placement="bottom"></button>

谢谢。

Answer 1

调用'show'时只需给出一个参数popover()

$('[data-toggle="popover"]').popover('show')

工作片段：

$(function () {
  $('[data-toggle="popover"]').popover('show')
})

<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/css/bootstrap.min.css" integrity="sha384-ggOyR0iXCbMQv3Xipma34MD+dH/1fQ784/j6cY/iJTQUOhcWr7x9JvoRxT2MZw1T" crossorigin="anonymous">
<script src="https://code.jquery.com/jquery-3.3.1.slim.min.js" integrity="sha384-q8i/X+965DzO0rT7abK41JStQIAqVgRVzpbzo5smXKp4YfRvH+8abtTE1Pi6jizo" crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.7/umd/popper.min.js" integrity="sha384-UO2eT0CpHqdSJQ6hJty5KVphtPhzWj9WO1clHTMGa3JDZwrnQq4sF86dIHNDz0W1" crossorigin="anonymous"></script>
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.3.1/js/bootstrap.min.js" integrity="sha384-JjSmVgyd0p3pXB1rRibZUAYoIIy6OrQ6VrjIEaFf/nJGzIxFDsf4x0xIM+B07jRM" crossorigin="anonymous"></script>

<button type="button" class="btn btn-secondary" data-container="body" data-toggle="popover" data-placement="bottom" data-content="Pop">Popover</button>
<button type="button" class="btn btn-secondary" data-container="body" data-toggle="popover" data-placement="bottom" data-content="Pop">Popover</button>
<button type="button" class="btn btn-secondary" data-container="body" data-toggle="popover" data-placement="bottom" data-content="Pop">Popover</button>

在页面刷新时显示弹出窗口

1 个答案: