Question

我目前有一种情况，当表达式向我显示员工执行的特定类型任务的总数。

select 
  ptt.user_id
  /*System Generated Counts*/ , 
  count(distinct case
    when menu_optn_name in ('Cycle Cnt {Active}','Cycle Cnt {Reserve}','Cycle Cnt Reserve (Tasking)') and task_id is not null then tran_nbr
    else null
  end) "Task Cnt"
  /*Spot Counts*/ , 
  count(distinct case
    when menu_optn_name in ('Cycle Cnt {Active}','Cycle Cnt {Reserve}') and task_id is null then tran_nbr
    else null
  end) "Spot_Counts", 
  count(distinct case
    when menu_optn_name in ('Cycle Cnt {Active}','Cycle Cnt {Reserve}','Cycle Cnt Reserve (Tasking)') and task_id is not null then tran_nbr
    when menu_optn_name in ('Cycle Cnt {Active}','Cycle Cnt {Reserve}','Cycle Cnt Reserve (Tasking)') and task_id is null then tran_nbr
    else null
  end) "Total_locations", 
  count(case
    when menu_optn_name in ('Cycle Cnt {Active}','Cycle Cnt {Reserve}','Cycle Cnt Reserve (Tasking)') and task_id is not null then tran_nbr
    when menu_optn_name in ('Cycle Cnt {Active}','Cycle Cnt {Reserve}','Cycle Cnt Reserve (Tasking)') and task_id is null then tran_nbr
    else null
  end) "Total_Cases"
from PROD_TRKG_TRAN ptt
  join cd_master cm on
    ptt.cd_master_id = cm.cd_master_id 
    and co = 'MEDT' 
    and div = '002' 
    and ptt.USER_ID in ('ARAMOS1','ECHAMBERS','SCOUNCIL','STORTEROTOT','TGABRIEL','JORTIZ','FGUTIERREZ','CMALDONADO','LLEE1') 
    and ptt.create_date_time >= 
/*Today*/ trunc(sysdate) 
--/*This Week*/              trunc(sysdate-(to_char(sysdate,'D')-1))
--/*This Month*/            trunc(sysdate)-(to_char(sysdate,'DD')-1)
--/*Date Range*/            '&FromDate' and ptt.create_date_time-1 < '&ToDate'
group by ptt.user_id

以上是我当前使用的SQL，在计算表达式时，前2种情况是根据特定选择器计算员工有多少个位置为空或不为空。接下来的2种情况，当表达式将二者组合在一起时，可以为您提供一夜中某个人所计数的总的不同位置，下一个表达式显示您所计数的总病例数，有时某个位置中有不止一个案例。 / p>

我在这里的目标是将地点和案件的总数除以7 1/2小时，这样我就可以看到一天中每小时平均有多少个人。我尝试了一些没有运气的东西。可能有人可以提供帮助。预先谢谢你。

划分数据记录

0 个答案: