我试图提示用户输入一个数字,然后询问他们是否要输入另一个。如果是,则重新启动第一个while循环,如果否,则退出以打印所选数字。
但是,无论我做什么,似乎都无法摆脱第一个循环。它只是不断重复编号。
我尝试将userInput =“ y”断开,然后在有效= true的末尾继续;当前是,它们都产生相同的结果。
陷入无限循环。
ArrayList<Integer> inputs = new ArrayList<Integer>();
System.out.println("Enter some numbers: ");
String userInput = "y";
boolean valid = false;
do {
while (scnr.hasNextInt()) {
inputs.add(scnr.nextInt());
System.out.println("Would you like to enter another?");
valid = true;
}
System.out.println(inputs);
} while (!userInput.equalsIgnoreCase("n"));
答案 0 :(得分:0)
问题在于您没有突破内循环。在这里,我将如何编写相同的代码:
import java.util.ArrayList;
import java.util.Scanner;
public class ReadNumbers {
public static void main(String[] args) {
ArrayList<Integer> inputs = new ArrayList<Integer>();
System.out.println("Enter some numbers: ");
try (Scanner scnr = new Scanner(System.in)) {
do {
inputs.add(scnr.nextInt());
System.out.println("Would you like to enter another y/n?");
} while (scnr.next().equalsIgnoreCase("y"));
}
System.out.println(inputs);
}
}
这将产生以下输出:
Enter some numbers:
14
Would you like to enter another y/n?
y
15
Would you like to enter another y/n?
y
17
Would you like to enter another y/n?
y
44
Would you like to enter another y/n?
n
[14, 15, 17, 44]
读取数字的另一种方法是从空格分隔的行中读取多个数字:
答案 1 :(得分:0)
我认为您过于复杂了。您只需要一个循环,一直运行到用户输入'n'。
在发生这种情况之前,请用户输入数字,将其读入,然后询问他们是否要继续。适当地更新循环条件,就可以完成:
public static void main(String... args) {
ArrayList<Integer> inputs = new ArrayList<Integer>();
try (Scanner scnr = new Scanner(System.in)) {
boolean valid = true;
while (valid) {
System.out.println("Enter some numbers: ");
if (scnr.hasNextInt()) {
inputs.add(scnr.nextInt());
}
System.out.println("Would you like to enter another?");
String response = scnr.next();
valid = response.trim().equalsIgnoreCase("y");
}
}
System.out.println(inputs);
}
产生输出
Enter some numbers:
1
Would you like to enter another?
y
Enter some numbers:
2
Would you like to enter another?
y
Enter some numbers:
3
Would you like to enter another?
n
[1, 2, 3]