<script> var show_menus = ['sub_menu_2', 'sub_menu_3']; var items = [{ label: 'menu1', items: [ { label: 'sub_menu_1', icon: 'fa-plus' }, { label: 'sub_menu_2', icon: 'fa-download' } ] }, { label: 'menu2', items: [ { label: 'sub_menu_3', icon: 'fa-refresh' }, { label: 'sub_menu_4', icon: 'fa-repeat' } ] }]; var my_menus = items.map(el => { return el.items; }); var menues_two = my_menus.filter(word =>{ }); </script>
答案 0 :(得分:1)
我想这就是你想要的。但是,如果不是这样,我可能会误解了您的问题。
var show_menus = ['sub_menu_2', 'sub_menu_3'];
var items = [{
label: 'menu1',
items: [{
label: 'sub_menu_1',
icon: 'fa-plus'
},
{
label: 'sub_menu_2',
icon: 'fa-download'
}
]
},
{
label: 'menu2',
items: [{
label: 'sub_menu_3',
icon: 'fa-refresh'
},
{
label: 'sub_menu_4',
icon: 'fa-repeat'
}
]
}
];
var my_menus = items.map(el => {
return el.items;
});
//console.log(my_menus);
var menues_two = [];
my_menus.forEach(word => {
var men = word.filter(elm => {
return show_menus.includes(elm['label']);
});
menues_two.push(men);
});
console.log(menues_two);