尝试从表“付款”到“付款历史”克隆数据(更新)
付款表
Payment_ID
Payment_Amount
Payment_Method
Payment_Remark
付款历史记录表
Payment_ID
Payment_Amount
Payment_Method
Payment_Remark
两者具有相同的列和相同的数据类型
我的代码: 控制器
public function updateHistory($Payment_ID){
// with single Payment_ID
//get data with specific column and ignore PaymentHistory_ID
$query = $this->db->select('Payment_Amount','Payment_Method','Payment_Remark')->where('Payment_ID', $Payment_ID)->get('YOUR FROM TABLE');
$result = $query->row_array();
if($result)
{ // check if has data
//then update to another table
$this->db->where('Payment_ID', $Payment_ID)->update('YOUR TO TABLE', $result ); // To update existing record
}
}
表数据
Payment Payment History
+-----+---------+ +------+------------+---------+
| ID | remark | | ID |remark | amount |
+=====+=========+ +======+============+=========+
| 1 |100 done | | 1 | 100 done | 100 |
+-----+---------+ +------+------------+---------+
| 2 |200 done | | 1 | 200 done | 200 |
+-----+---------+ +------+------------+---------+
| 2 | 500 done | 500 |
+------+------------+---------+
尝试使用数组克隆数据 上面是我的桌子的示例
答案 0 :(得分:0)
假设“付款表”名称为payment
,并且“付款历史”表名称为payment_history
,您可以尝试如下操作:
public function updateHistory($Payment_ID){
// with single Payment_ID
//get data with specific column and ignore PaymentHistory_ID
$query = $this->db->select('Payment_Amount','Payment_Method','Payment_Remark')
->where('Payment_ID', $Payment_ID)
->get('payment');
$result = $query->row_array();
if($result)
{ // check if has data
//then update to another table
$this->db->where('Payment_ID', $Payment_ID)->update('payment_history', $result ); // To update existing record
}
}