我正在尝试开发一个使用JavaMail发送电子邮件的Android应用程序。我已经尝试了下面的代码作为控制台应用程序,它的工作原理,但当我从模拟器中使用作为Android应用程序时,它抛出异常,没有消息。我修改了manifest.xml并放了
<uses-permission android:name="android.permission.INTERNET" />
但它仍然无效。 message.setText("Welcome to JavaMail");
会抛出异常,请帮助我!
我正在使用Sun的mail.jar
和activation.jar
。
Bellow是ClickHandler上的完整代码。
public void btnSendClickHandler(View view)
{
try{
String host = "smtp.gmail.com";
String from = "Username@gmail.com";
String pass = "Password";
Properties props = System.getProperties();
props.put("mail.smtp.starttls.enable", "true"); // added this line
props.put("mail.smtp.host", host);
props.put("mail.smtp.user", from);
props.put("mail.smtp.password", pass);
props.put("mail.smtp.port", "587");
props.put("mail.smtp.auth", "true");
String[] to = {"toEmailAddress@gmail.com"}; // added this line
Session session = Session.getDefaultInstance(props, null);
MimeMessage message = new MimeMessage(session);
message.setFrom(new InternetAddress(from));
InternetAddress[] toAddress = new InternetAddress[to.length];
// To get the array of addresses
for( int i=0; i < to.length; i++ ) {
toAddress[i] = new InternetAddress(to[i]);
}
for( int i=0; i < toAddress.length; i++) {
message.addRecipient(Message.RecipientType.TO, toAddress[i]);
}
message.setSubject("sending in a group");
message.setText("Welcome to JavaMail");//The exception is thrown here
Transport transport = session.getTransport("smtp");
transport.connect(host, from, pass);
transport.sendMessage(message, message.getAllRecipients());
transport.close();
} catch(Exception e){Toast.makeText(this, e.toString(),
Toast.LENGTH_LONG).show();
}}
答案 0 :(得分:0)
如果您使用以下内容设置正文,也许可以解决异常:
_multipart = new MimeMultipart();
BodyPart messageBodyPart = new MimeBodyPart();
messageBodyPart.setText("Welcome to JavaMail");
_multipart.addBodyPart(messageBodyPart);
message.setContent(_multipart);