P调用FormatMessage消息ByRef lpBuffer作为[String]无效

时间:2019-07-03 02:26:49

标签: vb.net pinvoke wininet kernel32

声明此功能:

    <DllImport("kernel32.dll", EntryPoint:="FormatMessageW", SetLastError:=True, CharSet:=CharSet.Unicode, CallingConvention:=CallingConvention.StdCall)>
Public Shared Function FormatMessage(ByVal dwFlags As Integer,
                                     ByRef lpSource As IntPtr,
                                     ByVal dwMessageId As Integer,
                                     ByVal dwLanguageId As Integer,
                                     ByRef lpBuffer As [String],
                                     ByVal nSize As Integer,
                                     ByRef Arguments As IntPtr) As Integer
End Function

基于此处的定义:https://pinvoke.net/default.aspx/kernel32/FormatMessage.html

场景
我目前正在Pwinvoking wininet.dll对服务器执行FTP事务。如果遇到错误,我会从 Err.LastDllError 返回错误代码。我定义了一个函数,该函数获取dll错误并根据错误代码返回一条消息,但是它无法按预期工作。这是我用来引发dll错误的函数:

Private Sub ThrowLastDllError()
    Dim iLastErrorID As Integer = Err.LastDllError
    Dim iMessageBuffer As IntPtr = Nothing
    Dim iModuleHandle As IntPtr = GetModuleHandle("wininet.dll")

    Dim sMessageBuffer As String = Nothing

    If iLastErrorID > 12000 And iLastErrorID < 12157 Then
        FormatMessage(FORMAT_MESSAGE_FROM_HMODULE Or
                     FORMAT_MESSAGE_IGNORE_INSERTS Or
                     FORMAT_MESSAGE_ALLOCATE_BUFFER,
                     iModuleHandle,
                     iLastErrorID,
                     0,
                     sMessageBuffer,
                     256,
                     Nothing)

        Debugger.Break()
        'TODO: Throw exception with error code message here
    End If
End Sub

基于此处描述的技术:https://docs.microsoft.com/en-us/windows/desktop/wininet/appendix-c-handling-errors我希望基于此特定dll的错误代码获得某种字符串消息,例如,如果我得到的错误代码为12110(ERROR_FTP_TRANSFER_IN_PROGRESS。参考: https://support.microsoft.com/en-au/help/193625/info-wininet-error-codes-12001-through-12156)如果不相同,我希望得到一条类似于以下内容的消息(在变量sMessageBuffer中):“由于正在进行某项操作,因此无法在FTP会话句柄上进行所请求的操作”。但是,sMessageBuffer永远不会分配值,并且什么也不会保留。我只能假设我以某种方式滥用了此技术,我尝试了在线论坛和此站点本身上描述的各种方法,但未成功。

1 个答案:

答案 0 :(得分:2)

以下一些有效的示例代码:

Sub Main()

    Dim h As IntPtr = LoadLibrary("wininet.dll") ' or GetModuleHandle ...
    Dim sb = New StringBuilder(1024)
    FormatMessage(Format_Message.FORMAT_MESSAGE_FROM_HMODULE Or Format_Message.FORMAT_MESSAGE_IGNORE_INSERTS,
        h,
        12002,
        0,
        sb,
        sb.Capacity,
        Nothing)

    Console.WriteLine(sb) ' prints "The operation timed out"
   ' FreeLibrary, etc.
End Sub

Enum Format_Message
    FORMAT_MESSAGE_IGNORE_INSERTS = &H200
    FORMAT_MESSAGE_FROM_SYSTEM = &H1000
    FORMAT_MESSAGE_FROM_HMODULE = &H800
End Enum

<DllImport("Kernel32", SetLastError:=True, CharSet:=CharSet.Unicode)>
Public Function FormatMessage(ByVal dwFlags As Format_Message, ByVal lpSource As IntPtr, ByVal dwMessageId As Integer, ByVal dwLanguageId As Integer, lpBuffer As StringBuilder, ByVal nSize As Integer, ByVal Arguments As IntPtr) As Integer
End Function

<DllImport("kernel32", SetLastError:=True, CharSet:=CharSet.Unicode)>
Public Function LoadLibrary(ByVal lpFileName As String) As IntPtr
End Function