我对此回应有一些疑问。我需要通过电子邮件显示用户数据和特定用户的所有消息。因此,我需要通过用户电子邮件将所有消息分组,并以html显示。
我需要遍历对象数组,并向用户显示电子邮件及其所有消息。您能帮我解决这个问题吗?预先感谢。
所以我得到了这样的东西:
[ { createdAt: '16-06-2019',
_id: 5d057bcff1b7df4e7d0d7ab0,
app_id: '2cd13022b821bb89a11a',
company_id: '5cf17a543d68d32a2e53cf9b',
user_id: '5d00b480f4534f2fcad63dad',
user_name: 'first user',
user_email: 'firstuser@gmail.com',
message: 'Omfg!',
message_status: 'unread',
},
{ createdAt: '16-06-2019',
_id: 5d06359549f4a71d6f78b78a,
app_id: '2cd13022b821bb89a11a',
company_id: '5cf17a543d68d32a2e53cf9b',
user_id: '5d00b480f4534f2fcad63dad',
user_name: 'first user',
user_email: 'firstuser@gmail.com',
message: 'Test msg',
message_status: 'unread',
},
{ createdAt: '17-06-2019',
_id: 5d07c7f6ac251d1c331cb20c,
app_id: '2cd13022b821bb89a11a',
company_id: '5cf17a543d68d32a2e53cf9b',
user_id: '5d07c6cdb979af1ac5aa25ec',
user_name: 'Second user',
user_email: 'seconduser@gmail.com',
message: 'msg from second user',
message_status: 'unread',
}
]
期望的结果应该是这样的:
[ { createdAt: '16-06-2019',
_id: 5d057bcff1b7df4e7d0d7ab0,
app_id: '2cd13022b821bb89a11a',
company_id: '5cf17a543d68d32a2e53cf9b',
user_id: '5d00b480f4534f2fcad63dad',
user_name: 'first user',
user_email: 'firstuser@gmail.com',
messages: ['Omfg!', Test msg ] -> group all messages by user email
message_status: 'unread',
},
{ createdAt: '17-06-2019',
_id: 5d07c7f6ac251d1c331cb20c,
app_id: '2cd13022b821bb89a11a',
company_id: '5cf17a543d68d32a2e53cf9b',
user_id: '5d07c6cdb979af1ac5aa25ec',
user_name: 'Second user',
user_email: 'seconduser@gmail.com',
messages: ['msg from second user'],
message_status: 'unread',
}
]
如果您有任何想法如何映射此对象数组以显示html中的用户电子邮件及其消息,请与我分享:)