Question

我有以下PHP。

最终，我希望执行结束时的输出为：

Size1Size3

$footballTypes = "1,3";

$footballTypeNames = "";

foreach ( $footballTypes as $data ) {
    switch ($data) {
      case 1:
        $footballTypeNames .= "Size 1";
      case 2:
        $footballTypeNames .= "Size 2";
      case 3:
        $footballTypeNames .= "Size 3";
    }
}

echo $footballTypeNames;

但是，现在，我得到了错误：

Warning: Invalid argument supplied for foreach() in C:\xampp\htdocs\football.php on line 7

我哪里出错了？

Answer 1

使用explode伴侣，

$footballTypes     = explode(",", "1,3"); // here I explode
$footballTypeNames = "";
foreach ($footballTypes as $data) {
    switch ($data) {
        case 1:
            $footballTypeNames .= "Size 1";break;
        case 2:
            $footballTypeNames .= "Size 2";break;
        case 3:
            $footballTypeNames .= "Size 3";break;
    }
}
echo $footballTypeNames;

Demo。

如果可以的话，有多种方法可以实现这一目标，
1。

$footballTypes     = explode(",", "1,3"); // here I explode
$temp = implode("",array_map(function($value){
    return "Size $value";
}, $footballTypes));
print_r($temp);

Demo

Answer 2

您不需要切换，因为您添加的文本仅为Size。使用爆炸和内爆..

implode（）函数从数组的元素中返回一个字符串。    语法：内爆（分隔符，数组）

explode（）函数将字符串分成数组。 语法：爆炸（分隔符，字符串，限制）

$footballTypes = "1,2,3";

$footballTypeNames = implode('Size ', explode(',',$footballTypes));


echo 'Size '.$footballTypeNames;

带foreach循环的简单开关盒

2 个答案: