我有以下JSON数据:
[{
"in_id": "1",
"in_name": "Education Point",
"in_email": "",
"in_pin": "834006"
}, {
"in_id": "2",
"in_name": "Vidya Coaching Center",
"in_email": "",
"in_pin": "834006"
}]
我想在select
标签中显示它。我正在尝试这样:
$.ajax({
type: 'post',
url: "<?=base_url()?>affiliates/get_institute/" + pin_code,
dataType: 'json',
success: function(data) {
var html = '';
var i;
for (i = 0; i < data.length; i++) {
html += "<option value='" + data[i].in_name + "'>" + data[i].in_name + "</option>";
}
$('select[name="sel_inst"]').append(html);
}
});
答案 0 :(得分:1)
您需要在HTML中添加<select name="sel_inst"></select>
。
您应该将in_id
设置为option的值,而不是in_name
我试图复制,但效果很好
var data = [{"in_id":"1","in_name":"Education Point","in_email":"","in_pin":"834006"},{"in_id":"2","in_name":"Vidya Coaching Center","in_email":"","in_pin":"834006"}];
var html = '';
var i;
for(i=0; i<data.length; i++){
html +="<option value='" +data[i].in_id+"'>"+data[i].in_name+"</option>";
}
$( 'select[name="sel_inst"]').append(html);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<select name="sel_inst"></select>
答案 1 :(得分:0)
Nguyen Hien说,您需要在HTML中添加选择标记。
并且您应该将in_id设置为option的值,而不是in_name
还使用sel_inst作为id,我决定改用foreach并成功
希望有帮助
let data = [{
"in_id": "1",
"in_name": "Education Point",
"in_email": "",
"in_pin": "834006"
}, {
"in_id": "2",
"in_name": "Vidya Coaching Center",
"in_email": "",
"in_pin": "834006"
}];
let selectBox = $('#sel_inst');
$.each(data,function(index,item){
$(selectBox).append('<option value="'+item.in_id+'" data-pin="'+item.in_pin+'">'+item.in_name+'</option>')
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<select name="sel_inst" id="sel_inst">
</select>