在我的数据库中,有两个表
我尝试使用以下查询来汇总json
SELECT coalesce(json_build_object(
'EventTypeID', ev."ID",
'EventTypeName', ev."Name",
'ActivityType', json_agg(json_build_object('ID',ac."ID",'Name',ac."Name",'ParentActivityType',json_agg(select * from "Activity" where ))
), '{}'::json) AS item
FROM "EventType" as ev
JOIN "ActivityType" as ac ON ev."ID" = ac."EventTypeID"
GROUP BY ev."ID"
预期的JSON输出
[{
"EventTypeID": 2,
"EventTypeName": "On-Site Care",
"ActivityType": [
{
"ID": 1,
"Name": "Measurement",
"EventTypeID": 2,
"ParentActivityTypeID": null,
"SubActivityType": [
{
"ID": 17,
"Name": "abc",
"EventTypeID": 2,
"ParentActivityTypeID": 1
}
]
},
{
"ID": 2,
"Name": "Medication",
"EventTypeID": 2,
"ParentActivityTypeID": null
},
{
"ID": 3,
"Name": "Wellness check",
"EventTypeID": 2,
"ParentActivityTypeID": null
},
{
"ID": 4,
"Name": "Other",
"EventTypeID": 2,
"ParentActivityTypeID": null
}
]
},
{
"EventTypeID": 3,
"EventTypeName": "Care Call",
"ActivityType": [
{
"ID": 1,
"Name": "Measurement",
"EventTypeID": 3,
"ParentActivityTypeID": null,
"SubActivityType": [
{
"ID": 17,
"Name": "abc",
"EventTypeID": 3,
"ParentActivityTypeID": 1
}
]
},
{
"ID": 2,
"Name": "Medication",
"EventTypeID": 3,
"ParentActivityTypeID": null
},
{
"ID": 3,
"Name": "Wellness check",
"EventTypeID": 3,
"ParentActivityTypeID": null
},
{
"ID": 4,
"Name": "Other",
"EventTypeID": 3,
"ParentActivityTypeID": null
}
]
}
]
答案 0 :(得分:0)
您可以按如下所述作为父表加入self表。
SELECT coalesce(json_build_object(
'EventTypeID', ev."ID",
'EventTypeName', ev."Name",
'ActivityType', json_agg(json_build_object('ID',ac."ID",'Name',ac."Name",'ParentActivityType',json_agg(parent.*))
), '{}'::json) AS item
FROM "EventType" as ev
LEFT JOIN "EventType" as parent ON ev."ParentActivityTypeID" = parent."ID"
JOIN "ActivityType" as ac ON ev."ID" = ac."EventTypeID"
GROUP BY ev."ID"