我的要求是整天将现有的每小时分区合并为每日分区。
我的分区列如下:
2019_06_22_00, 2019_06_22_01, 2019_06_22_02, 2019_06_22_03..., 2019_06_22_23 => 2019_06_22
2019_06_23_00, 2019_06_23_01, 2019_06_23_02, 2019_06_23_03..., 2019_06_23_23 => 2019_06_23
答案 0 :(得分:2)
简单的方法是从当前分区列中提取日期并加载到新表中。
创建新表:
create table new (
...
)
partitioned by (partition_date date);
然后从旧表中插入覆盖:
set hive.exec.dynamic.partition=true;
set hive.exec.dynamic.partition.mode=nonstrict;
insert overwrite table new partition(partition_date )
select
col1,
col2,
...
coln,
--extract hours if you need this column
substr('old_partition_col',12,2) hour,
--partition column is the last one
date(concat_ws('-',substr(old_partition_col,1,4),substr(old_partition_col,6,2),substr(old_partition_col,9,2))) as partition_date
from old_table;
或者,您可以使用unix_timestamp
和from_unixtime
函数提取日期:
from_unixtime(unix_timestamp(old_partition_col,'yyyy_MM_dd_HH'),'yyyy-MM-dd') as partition_date
然后删除旧表并重命名新表。