请帮助您处理请求,其中包含以下数据:您需要在状态列中将此数据分为一定间隔,以便使其大致如下所示:
client| date_start | date_end | status
-------------------------------------------------------
1 | 01.06.2019 0:00:00| 01.06.2019 0:02:00| 2
1 | 01.06.2019 0:02:00| 01.06.2019 0:04:00| 1
1 | 01.06.2019 0:04:00| 01.06.2019 0:05:00| 2
答案 0 :(得分:1)
这是一种扭曲的间隙和孤岛形式。您可以使用不同的行号来标识相邻的行。然后汇总并使用lead()
获取结束时间:
select client, status, min(time) as starttime,
lead(min(time)) over (partition by client order by min(time)) as endtime
from (select t.*,
row_number() over (partition by client order by time) as seqnum,
row_number() over (partition by client, status order by time) as seqnum_s
from t
) t
group by (seqnum - seqnum_s), status, client;