我是Java语言的新手,我想使用语音识别和文本到语音的网站构建一个聊天机器人。我做了开/关按钮,但是它不起作用。
我尝试过:
while (value == "on") {
utterance.volume = 1;
}
还
if (value == "on") {
utterance.volume = 1;
} else {
utterance.volume = 0;
}
但是仍然有问题。任何帮助
function onoff(){
currentvalue = document.getElementById('onoff').value;
if(currentvalue == "on"){
document.getElementById("onoff").value="on";
}else{
document.getElementById("onoff").value="off";
}
return currentvalue;
}
function speak(string){
var soundonoff = onoff();
var utterance = new SpeechSynthesisUtterance();
utterance.voice = speechSynthesis.getVoices().filter(function(voice)
{return voice.name == "Alex";})[0];
utterance.text = string;
utterance.lang = "en-US";
if (soundonoff == "on"){
utterance.volume = 1; //0-1 interval
}else{
terance.volume = 0;
}
utterance.rate = 0.8;
utterance.pitch = 1; //0-2 interval
speechSynthesis.speak(utterance);
}
答案 0 :(得分:1)
为此,有window.speechSynthesis的暂停和恢复方法;
要停止:
speechSynthesis.pause(); // pauses utterances being spoken
请参阅:pause
要继续:
speechSynthesis.resume(); /// resumes utters ,
请参阅resume
取消(停止)
speechSynthesisInstance.cancel();
请参阅cancel
根据您的条件,您可以调用这些方法
有关其他方法,请参见here
更新:-
这是粗略的代码,请根据您的要求进行更改
HTML:
<input type="checkbox" id="onoff" name="onoff" >On/Off<br>
<br/>
<input type="button" name="start" onclick="speak();" value ="start" > On/Off
<br>
脚本:
<script>
var synth = window.speechSynthesis;
function speak(){
var utterThis = new SpeechSynthesisUtterance('My pleasure, poke me up if you need more info.'); //
synth.speak(utterThis);
}
//// on check box change event call this
$('#onoff').change(function() {
if($("#onoff").prop('checked') == true){
speechSynthesis.pause();
/// now I dont know you want to pause or stop, change it according to you
///requirment
}
else {
speechSynthesis.pause();
}
});
</script>
GITHUB -sample project