我有2个用Swift 2编写的功能,但是Apple强迫我迁移到Swift 4,但我无法修复这些功能。
extension String {
func stringsMatchingRegularExpression(expression: String) -> [String] {
if let range = self.rangeOfString(expression, options: NSString.CompareOptions.RegularExpressionSearch, range: nil, locale: nil) {
return [self[range]] + self[range.endIndex..<self.endIndex].stringsMatchingRegularExpression(expression)
}
return []
}
func stringsMatchingRegularExpressionLarge(expression: String) -> [String] {
var result = [String]()
var currentRange = self.characters.indices
while let range = self.rangeOfString(expression, options: NSString.CompareOptions.RegularExpressionSearch, range: currentRange, locale: nil) {
result.append(self[range])
currentRange.startIndex = range.endIndex
}
return result
}
}
第一个函数的返回是我无法解决的问题。
第三行是Swift 4中的if let range = self.range(of: expression, options: NSString.CompareOptions.regularExpression, range: nil, locale: nil){
在第二个功能中,我不知道字符如何迁移。
答案 0 :(得分:3)
.characters
不见了。您可以直接使用字符串本身。
将self.characters.indices
更改为self.indices
将self.rangeOfString(expression, options: NSString.CompareOptions.RegularExpressionSearch, range: nil, locale: nil)
更改为self.range(of: expression, options: .regularExpression, range: nil, locale: nil)
最后,您可以使用NSRegularExpression
而不是递归地调用该函数,但是请注意,它可以throw
出现一些错误,因此您应该以某种方式进行处理。使用此扩展程序:
extension String {
func stringsMatchingRegularExpression(expression regex: String) throws -> [String] {
let regex = try NSRegularExpression(pattern: regex)
let results = regex.matches(in: self,
range: NSRange(self.startIndex..., in: self))
return results.map {
String(self[Range($0.range, in: self)!])
}
}
}
extension String {
func matching(expression regex: @autoclosure () throws -> NSRegularExpression) rethrows -> [String] {
let results = try regex().matches(in: self, range: NSRange(self.startIndex..., in: self))
return results.map {
String(self[Range($0.range, in: self)!])
}
}
func matching(pattern regexPattern: String) throws -> [String] {
return try self.matching(expression: NSRegularExpression(pattern: regexPattern))
}
}