我有一个来自远程API的json响应。在该JSON中,我有一个l2_list,它描述了各个子级的排序顺序。
我想根据“ l2_list”的顺序对子项进行排序。
我有一个如下的json数组:
var TreeObj = `{
"RULE_JSON":
{
"2674":{
"pid":"0",
"level":"1",
"mid":"2674",
"name":"test1",
"l2_list": [3083],
"children":
{
"3083":{"pid":"2674","level":"2","mid":"3083","name":"MAINTENANCE","children":[]}
}
},
"2619":{
"pid":"0",
"level":"1",
"mid":"2619",
"name":"EFFICIENCY",
"l2_list": [2605,2608,2607,2626,2627,3057,3058],
"children":
{
"2605":{"pid":"2619","level":"2","mid":"2605","name":"IDLING","children":[]},
"2607":{"pid":"2619","level":"2","mid":"2607","name":"COMPLIANT","children":[]},
"2626":{"pid":"2619","level":"2","mid":"2626","name":"DISPATCHED","children":[]},
"2627":{"pid":"2619","level":"2","mid":"2627","name":"HOURS","children":[]},
"2608":{"pid":"2619","level":"2","mid":"2608","name":"COMPLIANT DEPART","children":[]},
"3058":{"pid":"2619","level":"2","mid":"3058","name":"CENTER VISITS","children":[]},
"3057":{"pid":"2619","level":"2","mid":"3057","name":"OFFICE VISITS","children":[]}
}
}
}
}`;
排序后,我的结果集应显示2619个孩子,如下所示:
"l2_list": [2605,2608,2607,2626,2627,3057,3058],
"children":
{
"2605":{"pid":"2619","level":"2","mid":"2605","name":"IDLING","children":[]},
"2608":{"pid":"2619","level":"2","mid":"2608","name":"COMPLIANT DEPART","children":[]},
"2607":{"pid":"2619","level":"2","mid":"2607","name":"COMPLIANT","children":[]},
"2626":{"pid":"2619","level":"2","mid":"2626","name":"DISPATCHED","children":[]},
"2627":{"pid":"2619","level":"2","mid":"2627","name":"HOURS","children":[]},
"3057":{"pid":"2619","level":"2","mid":"3057","name":"OFFICE VISITS","children":[]},
"3058":{"pid":"2619","level":"2","mid":"3058","name":"CENTER VISITS","children":[]}
}
请帮助我
答案 0 :(得分:1)
假设变量a
中存储了对象
a = `{"l2_list": [2605,2608,2607,2626,2627,3057,3058],
"children":
{
"2605":{"pid":"2619","level":"2","mid":"2605","name":"IDLING","children":[]},
"2608":{"pid":"2619","level":"2","mid":"2608","name":"COMPLIANT DEPART","children":[]},
"2607":{"pid":"2619","level":"2","mid":"2607","name":"COMPLIANT","children":[]},
"2626":{"pid":"2619","level":"2","mid":"2626","name":"DISPATCHED","children":[]},
"2627":{"pid":"2619","level":"2","mid":"2627","name":"HOURS","children":[]},
"3057":{"pid":"2619","level":"2","mid":"3057","name":"OFFICE VISITS","children":[]},
"3058":{"pid":"2619","level":"2","mid":"3058","name":"CENTER VISITS","children":[]}
}}`
您可以填充按下一个代码排序的数组
sorted = [];
a.l2_list.forEach(number => {
let str = number.toString();
let obj = {};
obj[str] = a.children[str];
sorted.push(obj)
});