我有一个多维数组,我需要确定数组是否具有相同的'brand'属性值,然后返回其ID。
我尝试了一些数组函数,但是没有用。
我尝试过的事情:
1)
$backwards = array_reverse($attribute);
echo '<pre>';
$last_item = NULL;
$i = 0;
foreach ($backwards as $current_item) {
if ($last_item === $current_item[$i]['value']) {
echo '<pre>'; print_r($current_item[$i]['value']);
}
$last_item = $current_item[$i]['value'];
echo '<pre>'; print_r($last_item);
$i++;
}
2)
$j = 1;
$i = 0;
foreach ($attributeValues as $attributeData) {
foreach ($attribute as $value) {
if($value[$i]['value'] == $value[$j]['value']) {
echo '<pre>'; print_r($value); die();
}
$j++;
}
}
我所有的解决方案均无效,请帮忙。
[0] => Array
(
[0] => Array
(
[name] => brand
[value] => 54
[id] => 5251
[price] => 15000.0000
)
[1] => Array
(
[name] => model
[value] => 1200
[id] => 5251
[price] => 15000.0000
)
)
[1] => Array
(
[0] => Array
(
[name] => brand
[value] => 54
[id] => 5250
[price] => 15000.0000
)
[1] => Array
(
[name] => model
[value] => 1200
[id] => 5250
[price] => 12000.0000
)
)
[2] => Array
(
[0] => Array
(
[name] => brand
[value] => 89
[id] => 518
[price] => 100.0000
)
[1] => Array
(
[name] => model
[value] => 12
[id] => 518
[price] => 100
)
)
如果第一个数组的[name]=>brand
和[name]=>model
的值与第二个数组的值相同,则返回[id]
。
答案 0 :(得分:1)
您可以使用foreach
并遍历数组
$res = [];
foreach($arr as $k => $v){
if($v[0]['name'] == $v[1]['name'])
$res[$v[0]['name']] = $v[0]['id'];
}
如果要匹配索引value
,请尝试
foreach($arr as $k => $v){
if($v[0]['value'] == $v[1]['value'])
$res[] = $v[0]['id'];
}
答案 1 :(得分:1)
您需要两个for循环。
$result =[];
foreach ($arr as $key => $value) {
foreach($value as $v){
$result[$v['name']][] = $v['id'];
}
}
$result = array_map("array_unique", $result); // to make it unique
print_r($result);
// if you want to check ids for brand
//print_r($result['brand']);
输出:
Array
(
[brand] => Array
(
[0] => 5251
[1] => 5250
[3] => 518
)
[model] => Array
(
[0] => 5251
[1] => 518
)
)
Demo。
编辑
然后您可以按名称和值将其分组
$result =[];
foreach ($arr as $key => $value) {
foreach($value as $v){
$result[$v['name']."|".$v['value']][] = $v['id'];
}
}
$result = array_map("array_unique", $result);
print_r($result);die;
Demo。