Question

我做了一个表格，以便可以使用值更新数据库。我的问题是它与其他按钮冲突。其他按钮正在处理AJAX请求。但是，当它们处于表单形式时，它们将无法工作。所以我需要另一个解决方案。

我试图将最后一个按钮也设为AJAX请求，但无法获取发布值。

我所知道的：

function getUsers($orgID, $type)
{
    require 'functions/conn.php';

    $sql = "SELECT users.*, parts.*, keuze.* FROM ((users INNER JOIN parts ON users.part_id = parts.part_id) INNER JOIN keuze ON users.keuze_ID = keuze.ID) WHERE users.org_id = '" . $orgID . "' AND users.active IN ($type);";
    $result = $conn->query($sql);
    if ($result->num_rows > 0) {
        while ($row = $result->fetch_assoc()) {
            echo '<tr id="' . $row['user_id'] . '" class="changeUser">';
            echo '  <td><input type="checkbox" name="checked[]" value="' . $row['user_id'] . '"></td>';
            echo '  <td>' . $row['fnln'] . '</td>';
            echo '  <td>' . $row['username'] . '</td>';
            echo '  <td>' . $row['name'] . '</td>';
            echo '  <td>' . $row['keuze'] . '</td>';
            echo '  <td>';           
            if ($row['active'] == 0 && $row['eind_tijd'] != 0 || $row['active'] == 2 && $row['eind_tijd'] != 0) {
                echo '      <button class="button button-green" onclick="approveOne('.$row['user_id'].', '.$_SESSION['org_id'].')">Approve</button>';
            }
            echo '      <button class="button button-red" onclick="deleteFromRelation(' . $row['user_id'] . ');">Delete</button><br/>';
            echo '  </td>';
            echo '</tr>';
        }
    }
}
?>

 <form action="functions/save/saveAllusers.php" method="post" enctype="multipart/form-data">
     <div class="form-group col-md-12"><select name="tijd" class="form-control col-md-12" id="Eindtijd"><?php getTime(); ?></select></div>
     <input type="submit" name="submit" id="submitChangeUser" class="button button-green" value="Change time"/>
     <?php getUsers($_SESSION['org_id'], 0); getUsers($_SESSION['org_id'], 2); ?>
</form>

AJAX请求（PHP中的按钮）

function approveOne(user, org) {
    swal({
        title: 'Are you sure to approve this users?',
        type: 'warning',
        showCancelButton: true,
        confirmButtonColor: '#3085d6',
        cancelButtonColor: '#d33',
        confirmButtonText: 'Approve user'
    }).then(function () {
        $.ajax({
            url: "functions/save/approveUser.php",
            type: "POST",
            data: {user, org},
            success: function (data) {
                swal(
                    'Approved!',
                    'You have approved the selected user.',
                    'Success'
                );
                $("#newUsers").hide(250);
            },
            error: function (jXHR, textStatus, errorThrown) {
                alert(errorThrown);
            }
        });
    });
}

function deleteUser(userID) {
    swal({
        title: 'Are you sure you want to delete your user account?',
        text: "You can't revert this step.",
        type: 'warning',
        showCancelButton: true,
        confirmButtonColor: '#3085d6',
        cancelButtonColor: '#d33',
        confirmButtonText: 'Delete'
    }).then(function () {
        $.ajax({
            url: "functions/delete/deleteUser.php",
            type: "POST",
            data: {userID},
            success: function (data) {
                swal({
                    title: 'Deleted!',
                    text: 'You have deleted the user.',
                    type: 'success',
                }).then (function(){
                    //redirect de user
                    location.reload();
                });
            },
            error: function (errorThrown) {
                alert(errorThrown);
            }
        });
    }); 
}

我所期望的是，我可以更新行，就像我可以正确知道的那样，并且其他按钮可以正常工作。如果单击批准或删除按钮（php中的按钮），则它希望与html中的按钮相同。当然，它给出了无法插入的错误。但是按钮并不是为此而准备的……当它们离开表格时，它的工作原理就像正常情况一样。

使用复选框更新行，但与其他按钮冲突

0 个答案: