Question

我写了一个预测房价的代码。问题是，我获得的准确性得分为负。我使用了5种不同的算法，准确性得分无处不在。

我遇到的第一个问题是使用.map函数时收到警告，但我认为这不是问题。

回归模型有效，但是它们的训练和测试准确性无处不在。我也尝试过这个：

from sklearn.metrics import accuracy_score ... score_train = regression.accuracy_score(variables_train, result_train) ...

但是它向我显示了AttributeError：“ LinearRegression”对象没有属性“ accuracy_score”

您可以从此处下载数据库：

https://www.sendspace.com/file/93nkdy

这是代码：

import pandas as pd
from sklearn import linear_model
from sklearn.svm import SVR
from sklearn.tree import DecisionTreeRegressor

from sklearn.model_selection import train_test_split

#pandas display options
pd.set_option('display.max_rows', 70)
pd.set_option('display.max_columns', 100)
pd.set_option('display.width', 1000)

data = pd.read_csv("validate.csv")
data = data.drop(columns = ["id"])

data = data.dropna(axis='columns')

data_for_pred = data[["bedrooms_total", "baths_total",
                        "sq_ft_tot_fn", "garage_capacity",
                        "city", "total_stories", "rooms_total",
                        "garage", "flood_zone","price_closed"]]

#to see how many different values I have 
cities =  data_for_pred['city'].unique()
garage = data_for_pred['garage'].unique()
flood_zone = data_for_pred['flood_zone'].unique()

#mapping so that I can do my regression
data_for_pred['city'] = data_for_pred['city'].map({'Woodstock': 1, 'Barnard': 2, 'Pomfret': 3})
data_for_pred['garage'] = data_for_pred['garage'].map({'No': 0, 'Yes': 1})
data_for_pred['flood_zone'] = data_for_pred['flood_zone'].map({'Unknown': 0, 'Yes': 1, 'No': -1})

#print(data_for_pred)

def regression_model(bedrooms_num, baths_num, sq_ft_tot, garage_cap,
                    city, total_stor, rooms_tot, garage, flood_zone):


    classifiers = [
        ["Linear regression", linear_model.LinearRegression()],
        ["Support vector regression", SVR(gamma = 'auto')],
        ["Decision tree regression", DecisionTreeRegressor()],
        ["SVR - RBF", SVR(kernel = "rbf", C = 1e3, gamma = 0.1)],
        ["SVR - Linear regression", SVR(kernel = "linear", C = 1e0)]]

    variables = data_for_pred.iloc[:,:-1]
    results = data_for_pred.iloc[:,-1]

    predictionData = [bedrooms_num, baths_num, sq_ft_tot, garage_cap, city,
                      total_stor, rooms_tot, garage, flood_zone]

    info = ""

    for item in classifiers:

        regression = item[1]

        variables_train, variables_test, result_train, result_test = train_test_split(variables, results , test_size = 0.2, random_state = 4)

        regression.fit(variables_train, result_train)

        #Prediction
        prediction = regression.predict([predictionData])
        prediction = round(prediction[0], 2)

        #Accuracy of prediction
        score_train = regression.score(variables_train, result_train)
        score_train = round(score_train*100, 2)

        score_test = regression.score(variables_test, result_test)
        score_test = round(score_test*100, 2)

        info += str(item[0]) + " prediction: " + str(prediction) + " | Train accuracy: " + str(score_train) + "% | Test accuracy: " + str(score_test) + "%\n"

    return info


print(regression_model(7, 8, 4506, 0, 1, 2.00, 15, 0, 0)) #true value 375000
print(regression_model(8, 8, 5506, 0, 1, 2.00, 15, 0, 0)) #true value more then 375000

Answer 1

为分类问题定义了准确性。这里有一个回归问题。

.score的{{1}}方法返回预测的确定系数R ^ 2，而不是准确性。

score（self，X，y [，sample_weight]）返回系数确定预测的R ^ 2。

https://scikit-learn.org/stable/modules/generated/sklearn.linear_model.LinearRegression.html

编辑

如果您预测标签（分类问题），可以使用此。

LinearRegression

如果您预测标量值（回归问题）-这是您的情况，则应使用以下回归指标：

from sklearn.metrics import accuracy_score  
scores_classification = accuracy_score(result_train, prediction)

所有回归评分方法都在这里：https://scikit-learn.org/stable/modules/classes.html#module-sklearn.metrics

编辑2

使用：

scores_regr = metrics.mean_squared_error(y_true, y_pred)

Scikit-Learn在回归模型中的负准确性得分

1 个答案: