我无法在服务器上执行任何上传操作。与“玩游戏可以做的五件很酷的事情之一”相反,以下似乎不起作用:
public static void doSingleFileUpload(
Long id, @Required java.io.File upload, String description, String title
) {
Score score = Score.findById(id);
try {
score.files.add(new File(doFileUpload(new FileInputStream(upload), score), title));//PLAY crashes here, with a nullpointer exception on the upload parameter
} catch (IOException ex) {
//TODO: do something nice
}
score.save();
}
doFileUpload
看起来像这样:
@Check("registered")
private static String doFileUpload(InputStream is, Score score) throws IOException {
//get Score from db
//get dir if present
java.io.File dir = new java.io.File("/public/uploads/" + play.templates.JavaExtensions.slugify(score.title));
//if not, create
if (!dir.exists()) {
dir.mkdirs(); //create new dir if not present
}
//create file on server
java.io.File newfile = new java.io.File(dir, "testfile.txt");
OutputStream os = new FileOutputStream(newfile);
IOUtils.copy(is, os);
return newfile.getAbsolutePath();
}
有了这个观点:
<!-- ... -->
<form action="@{ScoreController.doSingleFileUpload()}" method="POST" enctype="multipart/form-data">
<input type="hidden" name="id" value="${score.id}" />
<input type="file" id="upload" name="upload" />
<input type="text" name="description" />
<input type="hidden" name="title" value="${score.title}" />
<input type="submit" value="submit" />
</form>
为什么upload
为空?我发现了类似的问题here。但是当我在POST之后查看标题时,除了playsession键之外,其中的信息非常少......
我做错了什么?
我正在测试FF4并使用Play 1.1.1。
编辑: 此示例应用程序适用于1.1.1和1.2。
控制器:
public class Application extends Controller {
public static void index() {
File dir = new File(Play.applicationPath+File.separator+"public"+File.separator+"uploads");
if (!dir.exists() && dir.isDirectory()) {
renderText("something went wrong");
} else {
String[] files = dir.list();
if (files != null) {
render(dir);
} else {
render();
}
}
}
public static void upload(File upload) throws FileNotFoundException, IOException {
File dir = new File(Play.applicationPath+File.separator+"public"+File.separator+"uploads");
if (!dir.exists()) {
dir.mkdirs();
}
File newfile = new File(dir, upload.getName());
FileInputStream fis = new FileInputStream(upload);
FileOutputStream fos = new FileOutputStream(newfile);
IOUtils.copy(fis, fos);
index();
}
}
查看:
#{extends 'main.html' /}
#{set title:'Home' /}
#{form @Application.upload(), enctype:'multipart/form-data'}
<input type="file" name="upload" />
<input type="submit" />
#{/form}
#{if (dir.list()!=null)}
<ul>
#{list items:dir.list(), as:'file'}
<li><a href="public/uploads/${file}">${file}</a></li>
#{/list}
</ul>
#{/if}
现在问题是:应用程序之间有什么区别,除了第一个应用程序有更多参数......
感谢大家到目前为止的帮助!
问候, 碧玉
答案 0 :(得分:2)
这会编译吗?您将java.io.File
对象传递给doFileUpload
,其第一个参数为InputStream
。
答案 1 :(得分:1)
不确定为什么你的代码不起作用,但是通过使用Blob而不是File,我得到了类似的工作。
public static void update(long userId,
String aboutMyself,
String location,
Blob profilePicBlob) {
UserProfile userProfile = UserProfile.find("select distinct upr from UserProfile upr where upr.user.id = ?", userId).first();
if(profilePicBlob != null) {
//TODO: Delete the old profile pic
userProfile.profilePic = new Pic(profilePicBlob).save();
}
userProfile.aboutMyself = aboutMyself;
userProfile.location = location;
userProfile.save();
show(userId);
}
@Entity
public class Pic extends Model {
public Blob image;
public Pic(Blob image) {
this.image = image;
}
}
#{form @UserProfileC.update(userProfile.user.id), enctype:'multipart/form-data'}
<div>
<div>About Myself:</div>
<textarea rows="10" cols="80" name="aboutMyself">${userProfile.aboutMyself</textarea>
</div>
<div>
<div>Location</div>
<input type="text" name="location" value="${userProfile.location}"/>
</div>
<div>
<input type="file" name="profilePicBlob" />
<label>${userProfile.profilePic == null ? 'Upload' : 'Change'} profile pic</label>
</div>
<div>
<input type="submit" value="Submit" id="postComment" />
</div>
#{/form}