Question

请您介绍一下在C＃中解析XML文档的最佳方法？

<RESPONSE>
  <FNAME>user1</FNAME>
  <LNAME>lastname1</LNAME>
  <ADDRESS>
     <LINE1>line 1 for user 1</LINE1>
     <LINE2>line 2 for user 1</LINE2>
     .....
     .....
  </ADDRESS>
  <FNAME>user2</FNAME>
  <LNAME>lastname2</LNAME>
  <ADDRESS>
     <LINE1>line 1 for user 2</LINE1>
     <LINE2>line 2 for user 2</LINE2>
     .....
     .....
  </ADDRESS>

</RESPONSE>

这是从在线XML服务返回的数据，它显然没有很好地形成，因为嵌套未适用于每个不同的元素。有没有办法可以避免逐行解析和文本比较？

Answer 1

你走了：

XmlTextReader xml = new XmlTextReader("response.xml");
while (xml.Read())
{
    switch (xml.NodeType)
    {
        case XmlNodeType.Element:
            {
                if (xml.Name == "RESPONSE") Console.WriteLine("Response: ");
                if (xml.Name == "FNAME")
                {
                    Console.Write("First Name: ");
                }
                if (xml.Name == "LNAME")
                {
                    Console.Write("Last Name: ");
                }
                if (xml.Name == "ADDRESS") Console.WriteLine("Address: ");
                if (xml.Name == "LINE1")
                {
                    Console.Write("Line 1: ");
                }
                if (xml.Name == "LINE2")
                {
                    Console.Write("Line 2: ");
                }
            }
            break;
        case XmlNodeType.Text:
            {
                Console.WriteLine(xml.Value);
            }
            break;
        default: break;
    }
}
Console.ReadKey();

Answer 2

Linq to Xml是使用.NET

解析XML的现代方法

以下代码段将为您提供对所有FNAME元素的访问权限

var doc = XDocument.Parse(xml);
foreach (var fname in doc.Root.Elements("FNAME") {
  // fname.Value has the element value
}

使用重复的节点模式解析XML

2 个答案: