Question

基本上，一旦发出POST请求并且API用JSON响应，我就需要在表视图中显示JSON数据。

我没有收到任何错误，但也没有收到调试器中显示的任何JSON响应。我不知道到底是什么问题，但似乎没有任何东西加载或显示在tableview中。

以下是我用来解释JSON的结构：

import UIKit

struct ScheduleStructure: Codable {
    let customer: String
    let PickedUpNUM: String
    let DeliveryNUM: String

}

这是JSON的样子：

[
    {
        "customer": “Example”,
        "PickedUpNUM": “2”,
        "DeliveryNUM": “4”
    }
]

这是当前的tableview控制器：

import UIKit



class ScheduleCell: UITableViewCell {
    @IBOutlet weak var cellStructure: UIView!
    @IBOutlet weak var testingCell: UILabel!
    @IBOutlet weak var pickupLabel: UILabel!
    @IBOutlet weak var deliveryLabel: UILabel!
}

class ScheduleTableViewController: UITableViewController {

    var driverName = UserDefaults.standard.string(forKey: "name")!


    var structure = [ScheduleStructure]()

    override func viewDidLoad() {
        super.viewDidLoad()
    UINavigationBar.appearance().isTranslucent = false

        self.view.backgroundColor = UIColor.white


        //Adds Shadow below navigation bar
        self.navigationController?.navigationBar.layer.masksToBounds = false
        self.navigationController?.navigationBar.layer.shadowColor = UIColor.lightGray.cgColor
        self.navigationController?.navigationBar.layer.shadowOpacity = 0.8
        self.navigationController?.navigationBar.layer.shadowOffset = CGSize(width: 0, height: 2.0)
        self.navigationController?.navigationBar.layer.shadowRadius = 2


        self.extendedLayoutIncludesOpaqueBars = true
        fetchJSON()
        let refreshControl = UIRefreshControl()
        refreshControl.addTarget(self, action: #selector(doSomething), for: .valueChanged)
        tableView.refreshControl = refreshControl

    }



    private func fetchJSON() {
        guard
            let url = URL(string: "https://example.com/example/example.php"),
            let value = driverName.addingPercentEncoding(withAllowedCharacters: .urlQueryValueAllowed)
            else { return }

        var request = URLRequest(url: url)
        request.httpMethod = "POST"
        request.httpBody = "value=\(value)".data(using: .utf8)

        URLSession.shared.dataTask(with: request) { data, _, error in
            DispatchQueue.main.async {
                //
            }
            }.resume()

    }

    @objc func doSomething(refreshControl: UIRefreshControl) {
        print("reloaded")

        fetchJSON()

    }



    override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return structure.count
    }

    override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {


        let cell = tableView.dequeueReusableCell(withIdentifier: "customerID", for: indexPath) as! ScheduleCell



        cell.textLabel?.font = .boldSystemFont(ofSize: 18)
        cell.textLabel?.textColor = UIColor.red

        let portfolio = structure[indexPath.row]

        cell.textLabel?.text = portfolio.customer


        return cell

    }

    override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {


        let cell = tableView.dequeueReusableCell(withIdentifier: "customerID", for: indexPath) as! ScheduleCell
        //cell.cellStructure.layer.cornerRadius = 50
        let portfolio = structure[indexPath.row]


        let navigationController = UINavigationController(rootViewController: controller)

        self.present(navigationController, animated: true, completion: nil)

    }


    override func viewWillAppear(_ animated: Bool) {
        fetchJSON()

    }



}

请告诉我是否有一种更好的方法

我只需要执行JSON POST并将结果显示在表中即可。

Answer 1

您需要将json响应解码为api回调内的数组

URLSession.shared.dataTask(with: request) { data, _, error in 
       guard let data = data else { return }
       do {
         self.structure = try JSONDecoder().decode([ScheduleStructure].self,from:data)
          DispatchQueue.main.async {
           self.tableView.reloadData()
          }
        }
        catch {
          print(error)
        } 

}.resume()

struct ScheduleStructure: Codable {
    let customer, pickedUpNUM, deliveryNUM: String

    enum CodingKeys: String, CodingKey {
        case customer
        case pickedUpNUM = "PickedUpNUM"
        case deliveryNUM = "DeliveryNUM"
    }
}

Answer 2

我假设您知道dataTask的主体实际上并未对其接收的数据做任何事情？那里只有一个空的评论。

我猜你想做这样的事情：

if let data = data {
    do {
        self.structure = try JSONDecoder().decode(Array<ScheduleStructure>.self, from: data)
        self.reloadData()
    } catch {
        print("TODO: handle parse error: \(error)")
    }
} else {
    print("TODO: handle network error: \(error)")
}

POST请求后，需要一些帮助来用JSON数据填充tableview

2 个答案: