答案 0 :(得分:0)
您需要将表自身连接到其中,并以价格作为连接条件。
类似
select distinct a.*
from book as a
join book as b on (a.price = b.price)
答案 1 :(得分:0)
Select price,group_concat(title)
from books
group by price having count(*) > 1
答案 2 :(得分:0)
以下查询将返回您期望的结果作为相同价格的标题:
SELECT title
FROM book
WHERE price IN (
SELECT price
FROM book
GROUP BY price
HAVING COUNT(price) > 1
)
答案 3 :(得分:0)
SELECT Group_concat(title)
FROM books
GROUP BY price
HAVING Count(*) >= 2;