为什么fopen文件夹失败？

Question

此代码有效。

pFile = fopen("d:\myfile.txt", "w");

此代码无效。

pFile = fopen("d:\ABC\myfile.txt", "w");

我确实有此文件夹d：\ ABC

OsS是Windows 10，使用Visual Studio 2019。

errno是22。

Answer 1

//these are all the same
char test1[]={'\n', '\a','\t','\\','\'','\"','\0'};
char test2[]={'\N', '\A','\T','\\','\'','\"','\0'};
char test3[]={10,7,9,92,39,34,0};
char test4[]={0x0a,0x07,0x09,0x5c,0x27,0x22,0x00};
char test5[]="\n\a\t\\\'\"";
char test6[]="\N\A\T\\\'\"";

使用的Microsoft文件

“ d：\\ ABC \\ myfile.txt”;

“ d：/ABC/myfile.txt”;

Answer 2

此行解决了问题：

pFile = fopen("D:\ABC\\myfile.txt", "r");