在我正在执行的页面上,我有四个选择下拉菜单,并且我希望第二,第三和第四选择菜单根据第一个选择下拉菜单中的选择显示数据库中的数据>
我更新了下面的代码,以查看上面的链接后又出现了另一个错误
说
注意:试图在第88行的index.php中获取非对象的属性
我有以下代码
<?php
include("db-connection.php");
// Tyre search setup
$widthSql = "SELECT DISTINCT 'width' FROM 'tyres' WHERE 'width' > 0 ORDER BY 'width'";
$widthResult = $conn->query($widthSql);
$profileSql = "SELECT DISTINCT 'profile' FROM 'tyres' WHERE 'profile' > 0 ORDER BY 'profile'";
$profileResult = $conn->query($profileSql);
$wheel_sizeSql = "SELECT DISTINCT 'wheel_size' FROM 'tyres' WHERE 'wheel_size' > 0 ORDER BY 'wheel_size'";
$wheel_sizeResult = $conn->query($wheel_sizeSql);
$speed_ratingSql = "SELECT DISTINCT 'speed_rating' FROM 'tyres' WHERE 'speed_rating' > 0 ORDER BY 'speed_rating'";
$speed_ratingResult = $conn->query($speed_ratingSql);
?>
<div class="form-group col-lg-3 col-md-3 col-sm-12">
<label>Width</label>
<div class="field-inner">
<select class="custom-select-box" name="width">
<?php
if ($widthResult->num_rows > 0) {
while($row = $widthResult->fetch_assoc()) { ?>
<option value="<?php echo $row['width'] ?>"><?php echo $row['width'] ?></option>
<?php }} ?>
</select>
<?php var_dump($widthResult); ?>
</select>
</div>
</div>
var_dump返回bool(false)