Question

我正在遵循这个https://jestjs.io/docs/en/bypassing-module-mocks，它基本上由一个createUser.js和一个玩笑组成。就我而言，我正在使用TypeScript

// createUser.ts
import fetch from 'node-fetch';

export const createUser = async () => {
  const response = await fetch('http://website.com/users', {method: 'POST'});
  const userId = await response.text();
  return userId;
};

// jest for createUser.ts
jest.mock('node-fetch');

import fetch from 'node-fetch';
const {Response} = jest.requireActual('node-fetch');

import {createUser} from './createUser';

test('createUser calls fetch with the right args and returns the user id', async () => {
  fetch.mockReturnValue(Promise.resolve(new Response('4')));

  const userId = await createUser();

  expect(fetch).toHaveBeenCalledTimes(1);
  expect(fetch).toHaveBeenCalledWith('http://website.com/users', {
    method: 'POST',
  });
  expect(userId).toBe('4');
});

尽管我没有收到本教程所述的TypeError: response.text is not a function，而是收到TypeError: Only absolute URLs are supported。

当我更改为fetch.mockReturnValue(Promise.resolve('http://website.com/users')时，TypeError: Only absolute URLs are supported消失了，我得到了TypeError: response.text is not a function。

那么，如何在笑话中模拟响应呢？

TypeError：仅支持绝对URL

0 个答案: