Question

假设我有下表：

NUM  TYPE  STAT   ERR
123   10      6    62
123   10      6    62
123   10      6    62
123   17      4     0
321   10      6    62
321   10      6    62

我当前正在使用以下查询：

select MIN(NUM) as NUMBER
     , MIN(STAT) as STATUS
     , MIN(ERR) as ERROR
     , MIN(retry) as RETRY 
 from TABLE_TB 
where ERR=62 
group by NUM 
having count(ERR) > 1;

输出将是：

NUM  TYPE  STAT   ERR  RETRY
123   10      6    62      3
321   10      6    62      2

没关系，但是我需要的是查询将仅输出NUM，具有ERR = 62，但也具有ERR = 0，排除那些具有ERR = 62但不具有ERR = 0的人。以第一个表为例，查询应该输出

NUM  TYPE  STAT   ERR  RETRY
123   10      6    62      3

这是因为NUM 123的ERR = 62（发生3次）而且ERR = 0。因此，NUM 321将被排除，因为即使ERR = 62，也没有ERR = 0。

希望是未来：）

非常感谢。卢卡斯

Answer 1

您可以使用子查询：

SELECT num
     , MIN(type) AS type
     , MIN(stat) AS status
     , MIN(err) AS err
     , COUNT(*) AS retry
FROM table_tb
WHERE err != 0 AND
      num IN (SELECT num FROM tb WHERE err = 0)
GROUP BY num;

或不使用子查询：

SELECT num
     , MIN(CASE WHEN err != 0 THEN type END) AS type
     , MIN(CASE WHEN err != 0 THEN stat END) AS stat
     , MIN(CASE WHEN err != 0 THEN err END) AS err
     , COUNT(CASE WHEN err != 0 THEN 1 END) AS retry
FROM table_tb
GROUP BY num
HAVING COUNT(DECODE(err, 0, 1)) > 0;

输出：

+-----+------+------+-----+-------+
| NUM | TYPE | STAT | ERR | RETRY |
+-----+------+------+-----+-------+
| 123 |   10 |    6 |  62 |     3 |
+-----+------+------+-----+-------+

Answer 2

您需要首先过滤err in (62, 0)上的表，然后找到您有多少种不同的错误类型（您需要2种，因为您有两个感兴趣的错误代码）。

一旦有了这些信息，就可以过滤err = 62且非重复计数= 2的行-例如：

WITH results as (select num,
                        type,
                        stat,
                        err,
                        retry,
                        count(distinct err) over (partition by num) num_err_types
                 from   table_tb
                 where  err in (62, 0))
select min(num) as nmbr,
       min(stat) as status,
       min(err) as ERROR,
       min(retry) as retry
from   results
where  err = 62
and    num_err_types = 2;

我使用了COUNT()分析函数来查找不同的计数-这样，无论错误代码如何，都将值添加到每一行，这使我们能够在最终查询中对其进行过滤。

Answer 3

或者您可以尝试这种简单而甜蜜的方式...

select MIN(NUM) as NUMBER
     , MIN(STAT) as STATUS
     , MAX(ERR) as ERROR
     , Count(*) as RETRY 
 from TestTable 
where ERR IN (62 ,0)
group by NUM 
having count(ERR) > 1 AND MIN(ERR)=0;

Oracle查询[需要子查询？]

3 个答案: