我陷入困境..我使用tipfy作为框架在scribd商店和blobstore上传文件。 我的webform with action不是由blobstore.create_upload_url创建的(我只是使用url_for('myhandler'))。我这样做是因为如果我使用blobstore处理程序解析了POST响应,我就不能使用普通的python-scribd api将文件上传到scribd store。 现在我有工作的涂鸦保护程序:
class UploadScribdHandler(RequestHandler, BlobstoreUploadMixin):
def post(self):
uploaded_file = self.request.files.get('upload_file')
fname = uploaded_file.filename.strip()
try:
self.post_to_scribd(uploaded_file, fname)
except Exception, e:
# ... get the exception message and do something with it
msg = e.message
# ...
# reset the stream to zero (beginning) so the file can be read again
uploaded_file.seek(0)
#removed try-except to see debug info in browser window
# Create the file
file_name = files.blobstore.create(_blobinfo_uploaded_filename=fname)
# Open the file and write to it
with files.open(file_name, 'a') as f:
f.write(uploaded_file.read())
# Finalize the file. Do this before attempting to read it.
files.finalize(file_name)
# Get the file's blob key
blob_key = files.blobstore.get_blob_key(file_name)
return Response('done')
def post_to_scribd(self, uploaded_file, fname):
errmsg =''
uploaded_file = self.request.files.get('upload_file')
fname = uploaded_file.filename.strip()
fext = fname[fname.rfind('.')+1:].lower()
if (fext not in ALLOWED_EXTENSION):
raise Exception('This file type does not allowed to be uploaded\n')
if SCRIBD_ENABLED:
doc_title = self.request.form.get('title')
doc_description = self.request.form.get('description')
doc_tags = self.request.form.get('tags')
try:
document = scribd.api_user.upload(uploaded_file, fname, access='private')
#while document.get_conversion_status() != 'DONE':
# time.sleep(2)
if not doc_title:
document.title = fname[:fname.rfind('.')]
else:
document.title = doc_title
if not doc_description:
document.description = 'This document was uploaded at ' + str(datetime.datetime.now()) +'\n'
else:
document.description = doc_description
document.tags = doc_tags
document.save()
except scribd.ResponseError, err:
raise Exception('Scribd failed: error code:%d, error message: %s\n' % (err.errno, err.strerror))
except scribd.NotReadyError, err:
raise Exception('Scribd failed: error code:%d, error message: %s\n' % (err.errno, err.strerror))
except:
raise Exception('something wrong exception')
正如你所看到它也将文件保存到blobstore中..但如果我上传大文件(即5Mb)我正在接收
RequestTooLargeError: The request to API call file.Append() was too large.
Request: docs.upload(access='private', doc_type='pdf', file=('PK\x03\x04\n\x00\x00\x00\x00\x00"\x01\x10=\x00\x00(...)', 'test.pdf'))
我该如何解决? 谢谢!
答案 0 :(得分:7)
您需要对文件API进行多次较小的调用,例如:
with files.open(file_name, 'a') as f:
data = uploaded_file.read(65536)
while data:
f.write(data)
data = uploaded_file.read(65536)
请注意,对App Engine应用程序的常规请求的有效负载大小限制为10MB;如果你想上传更大的文件,你需要使用常规的blobstore上传机制。
答案 1 :(得分:6)
最后我找到了解决方案。
Nick Johneson的回答发生属性错误,因为uploaded_file被视为字符串。 string没有read()方法。
原因字符串没有方法read(),我拼接文件字符串,就像他写的那样写。
class UploadRankingHandler(webapp.RequestHandler):
def post(self):
fish_image_file = self.request.get('file')
file_name = files.blobstore.create(mime_type='image/png', _blobinfo_uploaded_filename="testfilename.png")
file_str_list = splitCount(fish_image_file,65520)
with files.open(file_name, 'a') as f:
for line in file_str_list:
f.write(line)
你可以检查一下splitCount()。这里