我目前正在解决一个问题,建议使用“ Pandas”,因为它适合我的解决方案,所以道歉,因为我是“ Pandas”软件包的新手。
我要解决的问题是读取带有以下数据的文本文件:
EmpID,ProjectID,DateFrom,DateTo
1,100,2014-11-01,2015-05-01
2,101,2013-12-06,2014-10-06
3,102,2015-06-04,2017-09-04
5,103,2014-10-01,2015-12-01
2,100,2013-03-07,2015-11-07
2,103,2015-07-09,2019-01-19
4,102,2013-11-13,2014-03-13
4,103,2016-02-14,2017-03-15
5,104,2014-03-15,2015-11-09
现在我的任务是说哪个员工在一个共同的项目上工作时间最长。
这是我到目前为止的进展:
import pandas as pd
import datetime as dt
import numpy as np
date_parser = lambda c: pd.to_datetime(c, format='%Y/%m/%d', errors='coerce')
df = pd.read_csv('data.csv', delimiter = ',', parse_dates=[2,3], date_parser=date_parser)
#df.set_index("EmpID", inplace = True)
df.sort_values(['ProjectID'], inplace=True)
df['Days Worked'] = (df['DateTo'] - df['DateFrom']).dt.days
cutdown_projecs = df.groupby('ProjectID').filter(lambda x: len(x) >= 2)
print(cutdown_projecs)
我要做的是对表格进行排序,使日期值设置为正确的格式,按ProjectID排序,然后缩减为重复两次或多次的项目(因为这将意味着员工需要共同努力)。我还添加了一个新列,其中添加了“工作天数”。这导致我得到以下结果:
EmpID ProjectID DateFrom DateTo Days Worked
0 1 100 2014-11-01 2015-05-01 181
4 2 100 2013-03-07 2015-11-07 975
2 3 102 2015-06-04 2017-09-04 823
6 4 102 2013-11-13 2014-03-13 120
3 5 103 2014-10-01 2015-12-01 426
5 2 103 2015-07-09 2019-01-19 1290
7 4 103 2016-02-14 2017-03-15 395
现在,我需要有关如何正确解决问题的建议。我不知何故需要检查哪个数据范围在同一项目中“冲突”,然后一起计算员工的工作日。如果您能给我小费,我将不胜感激。谢谢。
编辑:修复了表格。
答案 0 :(得分:2)
我拼凑出一个解决方案,但不知道它是否满足您的需求。由2名员工共同完成工作的时间最长。
from collections import defaultdict
from itertools import combinations
from datetime import datetime
data ='''\
1,100,2014-11-01,2015-05-01
2,101,2013-12-06,2014-10-06
3,102,2015-06-04,2017-09-04
5,103,2014-10-01,2015-12-01
2,100,2013-03-07,2015-11-07
2,103,2015-07-09,2019-01-19
4,102,2013-11-13,2014-03-13
4,103,2016-02-14,2017-03-15
5,104,2014-03-15,2015-11-09'''.splitlines()
d = defaultdict(list)
for line in data:
empID, job, start, finish = line.split(',')
d[job].append([empID,start,finish])
for job, aref in d.items():
if len(aref) >= 2:
for ref in combinations(aref, 2):
begin = max(map(lambda x: x[1], ref))
end = min(map(lambda x: x[2], ref))
delta = datetime.strptime(end, '%Y-%m-%d') \
- datetime.strptime(begin, '%Y-%m-%d')
dd = delta.days
if dd > 0:
print('employees', ref[0][0], 'and', ref[1][0],
'worked together', dd, 'days on job', job)
输出为:
employees 1 and 2 worked together 181 days on job 100
employees 5 and 2 worked together 145 days on job 103
employees 2 and 4 worked together 395 days on job 103
>>>