Question

我的解决方案中有多个项目，并且我对每个客户请求的自定义项使用了替代项，以使代码尽可能地井井有条。在这个特定的替代中，我试图从基类继承以进行序列化，但是在尝试进行序列化时遇到错误。

//In the Base project serialization works 100%
namespace Template
{
    //[XmlInclude(typeof(StaticText))]
    //[XmlInclude(typeof(BoundText))]
    //[XmlInclude(typeof(StaticImage))]
    //[XmlInclude(typeof(BoundImage))]
    //[XmlInclude(typeof(Font))]
    public class objType
    {
        public float X { get; set; }
        public float Y { get; set; }
        public float Height { get; set; }
        public float Width { get; set; }
    }

    public class ObjMain()
    {
        public string ObjName { get; set; }
        public List<objType> ObjTypeItems { get; set; }
    }

    public class DoWork() {
        using (System.IO.TextReader tr = new System.IO.StringReader(templateXML))
        {
            System.Xml.Serialization.XmlSerializer serializer = new System.Xml.Serialization.XmlSerializer(typeof(ObjMain));
            bg = (ObjMain)serializer.Deserialize(tr);
        }
    }
}



/*
<ObjMain>
    <ObjName>Section 1</ObjName>
    <ObjTypeItems>
        <objType xsi:type="StaticText">
            <X>32.5</X>
            <Y>4.35</Y>
            <Height>10</Height>
            <Width>20</Width>
            <TextFieldName>M</TextFieldName>
        </objType> 
        <objType xsi:type="BountText">
            <X>32.5</X>
            <Y>4.35</Y>
            <Height>10</Height>
            <Width>20</Width>
            <TextFieldName>Mat</TextFieldName>
        </objType> 
    </ObjTypeItems>    
</ObjMain>
*/


namespace CustomTemplate
{
[XmlInclude(typeof(StaticText))]
    [XmlInclude(typeof(BoundText))]
    [XmlInclude(typeof(StaticImage))]
    [XmlInclude(typeof(BoundImage))]
    [XmlInclude(typeof(Font))]
    public class CustomObjType : objType
    {
        public string GroupName { get; set; }
    }

    public class CustomObjMain()
    {
        public string CObjName { get; set; }
        public List<CustomObjType> CObjTypeItems { get; set; }
    }

    public class DoWork() {
        using (System.IO.TextReader tr = new System.IO.StringReader(templateXML))
        {
            System.Xml.Serialization.XmlSerializer serializer = new System.Xml.Serialization.XmlSerializer(typeof(CustomObjMain));//Error
            bg = (CustomObjMain)serializer.Deserialize(tr);
        }
    }

}

/*
<CustomObjMain>
    <CObjName>Section 1</CObjName>
    <ObjTypeItems>
        <CustomObjType xsi:type="StaticText">  <!--Error when with Serialization -->
            <X>32.5</X>
            <Y>4.35</Y>
            <Height>10</Height>
            <Width>20</Width>
            <TextFieldName>M</TextFieldName>
            <GroupName>MainGroup</GroupName>
        </CustomObjType> 
        <CustomObjType xsi:type="BountText">
            <X>32.5</X>
            <Y>4.35</Y>
            <Height>10</Height>
            <Width>20</Width>
            <TextFieldName>Bar</TextFieldName>
            <GroupName>MainGroup</GroupName>
        </CustomObjType> 
        <CustomObjType xsi:type="BountText">
            <X>32.5</X>
            <Y>4.35</Y>
            <Height>10</Height>
            <Width>20</Width>
            <TextFieldName>Foo</TextFieldName>
            <GroupName>SubGroupFoo</GroupName>
        </CustomObjType> 
    </ObjTypeItems>    
</CustomObjMain>
*/

我的感觉是类属性未随基类继承。但是我也尝试将属性添加到从基类继承的类中，但是很幸运，该错误继续在第一行的xml中显示，并在其中添加了“ xsi：type =”。

Answer 1

尝试以下操作：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Serialization;

namespace ConsoleApplication5
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            ObjMain objects = new ObjMain()
            {
                ObjName = "Main",
                objects = new List<ObjMain>() {
                    new objType1 { ObjName = "type 1" , X = 1.0F, Y = 2.0F, Height = 5F, Width = 10F},
                    new objType2 { ObjName = "type 2" , X = 1.5F, Y = 2.5F, Height = 5.5F, Width = 10.5F}
                }
            };

            XmlWriterSettings settings = new XmlWriterSettings();
            settings.Indent = true;
            XmlWriter writer = XmlWriter.Create(FILENAME, settings);
            XmlSerializer serializer = new XmlSerializer(typeof(ObjMain));
            serializer.Serialize(writer, objects);


        }
    }
    public class objType1 : ObjMain
    {
        public float X { get; set; }
        public float Y { get; set; }
        public float Height { get; set; }
        public float Width { get; set; }
    }
    public class objType2 : ObjMain
    {
        public float X { get; set; }
        public float Y { get; set; }
        public float Height { get; set; }
        public float Width { get; set; }
    }

    [XmlInclude(typeof(objType1))]
    [XmlInclude(typeof(objType2))]
    public class ObjMain
    {
        public string ObjName { get; set; }
        [XmlElement()]
        public List<ObjMain> objects { get; set; }
    }
}

如何在继承自具有有效“ XmlInclude”属性的基类的类上包含“ XmlInclude”？

1 个答案: