Question

这是自动配对星号（用于Markdown和AsciiDoc）文件的按键图。有用。问题：

1）我是否应该在第一个区块的第六行中避开星号？

2）在我的测试中，此行的转义没有任何区别。但为什么？如果您尝试删除最后一个块的第5行和第6行（以及第5个块中的行）中的转义，将导致错误的行为。因此，此处需要转义。但似乎在第一个块中并不需要。这让我感到困惑。

[
    // Auto-pair *
    { "keys": ["*"], "command": "insert_snippet", "args": {"contents": "*$0*"}, "context":
        [
            { "key": "setting.auto_match_enabled", "operator": "equal", "operand": true },
            { "key": "selection_empty", "operator": "equal", "operand": true, "match_all": true },
            { "key": "following_text", "operator": "regex_contains", "operand": "^(?:\t| |\\)|]|\\}|>|$)", "match_all": true },
            { "key": "preceding_text", "operator": "not_regex_contains", "operand": "[\\*a-zA-Z0-9_]$", "match_all": true }, // --- THIS line ---
            { "key": "eol_selector", "operator": "not_equal", "operand": "string.quoted.other - punctuation.definition.string.end", "match_all": true }
        ]
    },
    { "keys": ["*"], "command": "insert_snippet", "args": {"contents": "*${0:$SELECTION}*"}, "context":
        [
            { "key": "setting.auto_match_enabled", "operator": "equal", "operand": true },
            { "key": "selection_empty", "operator": "equal", "operand": false, "match_all": true }
        ]
    },
    { "keys": ["*"], "command": "move", "args": {"by": "characters", "forward": true}, "context":
        [
            { "key": "setting.auto_match_enabled", "operator": "equal", "operand": true },
            { "key": "selection_empty", "operator": "equal", "operand": true, "match_all": true },
            { "key": "following_text", "operator": "regex_contains", "operand": "^\\*", "match_all": true }, // --- THIS line ---
            { "key": "selector", "operator": "not_equal", "operand": "punctuation.definition.string.begin", "match_all": true },
            { "key": "eol_selector", "operator": "not_equal", "operand": "string.quoted.other - punctuation.definition.string.end", "match_all": true },
        ]
    },
    { "keys": ["backspace"], "command": "run_macro_file", "args": {"file": "res://Packages/Default/Delete Left Right.sublime-macro"}, "context":
        [
            { "key": "setting.auto_match_enabled", "operator": "equal", "operand": true },
            { "key": "selection_empty", "operator": "equal", "operand": true, "match_all": true },
            { "key": "preceding_text", "operator": "regex_contains", "operand": "\\*$", "match_all": true }, // --- THIS line ---
            { "key": "following_text", "operator": "regex_contains", "operand": "^\\*", "match_all": true }, // --- THIS line ---
            { "key": "selector", "operator": "not_equal", "operand": "punctuation.definition.string.begin", "match_all": true },
            { "key": "eol_selector", "operator": "not_equal", "operand": "string.quoted.other - punctuation.definition.string.end", "match_all": true },
        ]
    },
]

更新：实际上，最好使用另一个正则表达式：

- [*a-zA-Z0-9_]$
+ (^[*\\s]*$)|([*a-zA-Z0-9_]$)

这样，当您使用项目符号列表时，星号将不会在行的开头重复。

Answer 1

在正则表达式中，*运算符很特殊，表示前一个原子的<零>个或多个重复。因此，为了匹配文字*，您需要将其转义为\*（或在JSON \\*中）以向正则表达式引擎表明您是文字*而不应用特殊含义。

构造[]代表character set，它与集合中的任何字符匹配。在字符集内，对正则表达式引擎具有特殊含义的唯一字符是]（关闭字符集），\（仍需要转义），-（指定一定范围的字符）和^（否定集合，并且只有在第一个字符时才是特殊字符），因此只有那些字符需要在集合内转义。

由于字符集的意思是匹配以下任意一个字符，*的特殊含义不适用，因此在字符集内部无需转义（尽管您仍然可以这样做）。

键盘映射文件中的字符转义

1 个答案: