我需要将数据从一个Hive源表复制到另一目标表。下面是带有示例数据的源表结构:
source_table
Userid Name Phone1 Phone2 Phone3 Address1 Address2 Address3
123 Jitu 123456 987654 111111 DELHI GURGAON NOIDA
234 Mark 123456 987654 111111 UK USA IND
将数据从源复制到目标时,我的要求是要具有Phone1,Phone2,Phone3以及相应的Address1,Address2和Address3 目标表中单个列中的列。以下是目标表中数据的外观:
Target_table
Userid Name Phone_no Address
123 Jitu 123456 DELHI
123 Jitu 987654 GURGAON
123 Jitu 111111 NOIDA
234 Mark 123456 UK
234 Mark 987654 USA
234 Mark 111111 IND
我知道最简单的方法是对源表中的每个Phone和address列对目标表进行多次插入 使用配置单元查询语言或spark数据框。
还有其他有效的方法可以用来实现这一目标。
答案 0 :(得分:4)
对于每个列索引,可以多次选择原始数据框,然后将选定的数据框通过“联合”组合为一个:
val df = Seq(
(123, "Jitu", "123456", "987654", "111111", "DELHI", "GURGAON", "NOIDA"),
(234, "Mark", "123456", "987654", "111111", "UK", "USA", "IND")
).toDF(
"Userid", "Name", "Phone1", "Phone2", "Phone3", "Address1", "Address2", "Address3"
)
val columnIndexes = Seq(1, 2, 3)
val onlyOneIndexDfs = columnIndexes.map(idx =>
df.select(
$"Userid",
$"Name",
col(s"Phone$idx").alias("Phone_no"),
col(s"Address$idx").alias("Address")))
val result = onlyOneIndexDfs.reduce(_ union _)
输出:
+------+----+--------+-------+
|Userid|Name|Phone_no|Address|
+------+----+--------+-------+
|123 |Jitu|123456 |DELHI |
|123 |Jitu|111111 |NOIDA |
|123 |Jitu|987654 |GURGAON|
|234 |Mark|123456 |UK |
|234 |Mark|987654 |USA |
|234 |Mark|111111 |IND |
+------+----+--------+-------+
答案 1 :(得分:2)
以防万一,如果您也对Hive感兴趣,那么在连接多个数组结果集时,横向视图会产生笛卡尔乘积。您可以使用posexplode达到相同的结果,如下所示:
select Userid,Name,phone,address
from source_table
lateral view posexplode(array(Phone1,Phone2,Phone3)) valphone as x,phone
lateral view posexplode(array(Address1,Address2,Address3)) valaddress as t,address
where x=t
;
hive> set hive.cli.print.header=true;
userid name phone address
123 Jitu 123456 DELHI
123 Jitu 987654 GURGAON
123 Jitu 111111 NOIDA
234 Mark 123456 UK
234 Mark 987654 USA
234 Mark 111111 IND
Time taken: 2.759 seconds, Fetched: 6 row(s)