Question

我有带有Integration和Spring Data JPA的Spring引导应用程序。配置如下：

Application.class：

@SpringBootApplication
public class Application {

    public static void main(String[] args) {
        SpringApplication.run(Application.class, args);
    }
}

IntegrationConfiguration.class

@Configuration
@EnableIntegration
public class IntegrationConfiguration {
    private static final String FILE_PATTERN = "*.XML";

    @Value("${spring.integration.input-directory}")
    private String inputDirectory;
    @Value("${spring.integration.output-directory}")
    private String outputDirectory;
    @Value("${spring.integration.threads}")
    private int threadsCount;
    @Resource
    private ActualStatusRepository actualStatusRepository;

    //. . . removed file splitter and channels

    @Bean(name = "fiasEntityRouter")
    @Router(inputChannel = "afterSplitChannel")
    AbstractMappingMessageRouter fiasEntityRouter() {
        Map<String, String> routingMap = ImmutableMap.<String, String>builder()
                .put("ru.ecoteck.entity.ActualStatus", "actualStatusChannel")
                .build();
        PayloadTypeRouter router = new PayloadTypeRouter();
        router.setChannelMappings(routingMap);
        router.setDefaultOutputChannel(logChannel());
        return router;
    }

    @Bean(name = "actualStatusChannel")
    public MessageChannel actualStatusChannel() {
        return new DirectChannel();
    }

    @Bean(name = "actualStatusHandler")
    @ServiceActivator(inputChannel = "actualStatusChannel")
    public MessageHandler actualStatusHandler() {
        return new ActualStatusHandler(actualStatusRepository);
    }
}

因此，该应用程序开始读取XML文件，将它们拆分成小块，通过XStream反序列化，然后保存该对象，我得到一个错误，指出表actual_statuses不存在。但是在我的@Entity带注释的类中，我使用了名为ActualStatuses

的表

@XStreamAlias("ActualStatus")
@Entity
@Table(name = "ActualStatuses")
public class ActualStatus {

    @XStreamAsAttribute
    @XStreamAlias("ACTSTATID")
    @Id
    @Column(name = "ACTSTATID", nullable = false)
    private int id;

    // . . .
}

ActualStatusHandler只是在调用repository.save(message.getPayload)，但带有一些保护代码。似乎仅在搜索@Entity类时才出现问题。春季启动版本是2.1.5.RELEASE。我尝试了显式注释@EntityScan("my.package.entity")，但没有任何效果。我不使用任何自定义数据库层配置。只是application.properties

#database
spring.datasource.url=jdbc:postgresql://localhost:5432/fias
spring.datasource.username=fias
spring.datasource.password=fias
spring.datasource.driverClassName=org.postgresql.Driver
spring.jpa.hibernate.ddl-auto=none
spring.jpa.open-in-view=false
spring.jpa.properties.hibernate.jdbc.lob.non_contextual_creation=true
spring.jpa.properties.hibernate.dialect=org.hibernate.dialect.PostgreSQL95Dialect
# for debug
spring.jpa.show-sql=true

出了什么问题？非常感谢您的帮助。

Answer 1

因此，参数

spring.jpa.hibernate.naming.physical-strategy=org.hibernate.boot.model.naming.PhysicalNamingStrategyStandardImpl

做到了这一点，现在应用程序可以按预期工作。感谢 Patrick 为我指出正确的挖掘方向。

@EntityScan不扫描

1 个答案: