如何获得触发两种方法的按钮?

时间:2019-05-26 20:30:09

标签: java android button

我正在Android Studio中使用我的onClick方法创建此TicTacToe游戏,我会画一个X或O,并检查是否有人获胜。我的问题是,当某人要进行获胜的举动时,它只会执行获胜的方法,而不会执行绘制X或O的方法,因此游戏会终止而不会绘制最后一个字母

public class button1 extends AppCompatActivity implements View.OnClickListener {
private Button[][] buttons = new Button[3][3];
private boolean player1Turn = true;
private int roundCount =0;
private int player1Points =0;
private int player2Points =0;

private TextView textViewPlayer1;
private TextView textViewPlayer2;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_button1);
    textViewPlayer1 = findViewById(R.id.player1__number_score);
    textViewPlayer2 = findViewById(R.id.player2__number_score);

    for(int i=0; i<3; i++){
        for (int j=0; j<3; j++){
            String buttonID = "button_" + i + j;
            int resID = getResources().getIdentifier(buttonID, "id", getPackageName());
            buttons[i][j] = findViewById(resID);
            buttons[i][j].setOnClickListener(this);
        }
    }
}



@Override
public void onClick(View view){
    if(!((Button) view).getText().toString().equals("")){
        return;
    }
    if(player1Turn) {
        ((Button) view).setText("X");
    }else{
        ((Button) view).setText("O");

    }
    roundCount++;
    if(checkForWin()){
        if(player1Turn){
            player1Wins();
        }
        else{
            player2Wins();
        }
    } else if(roundCount == 9){
        draw();
    }else{
        player1Turn =!player1Turn;
    }

}
private boolean checkForWin(){
    String[][] check = new String[3][3];
    for(int i = 0; i<3; i++){
        for(int j=0; j<3; j++){
            check[i][j] = buttons[i][j].getText().toString();

        }
    }
    for (int i=0; i<3; i++){
        if (check[i][0].equals(check[i][1]) && check[i][0].equals(check[i][2]) && !check[i][0].equals("")){
            return true;
        }

    }
    for (int i=0; i<3; i++){
        if (check[0][i].equals(check[1][i]) && check[0][i].equals(check[2][i]) && !check[0][i].equals("")){
            return true;
        }

    }
    if (check[0][0].equals(check[1][1]) && check[0][0].equals(check[2][2]) && !check[0][0].equals("")){
        return true;
    }
    if (check[0][2].equals(check[1][1]) && check[0][2].equals(check[2][0]) && !check[0][2].equals("")){
        return true;
    }
    return false;
}
private void player1Wins() {
    player1Points++;
    textViewPlayer1.setText(Integer.toString(player1Points));
    Toast.makeText(this,"Player 1 has won",Toast.LENGTH_SHORT).show();
    resetBoard();

}


private void player2Wins(){
    player2Points++;
    textViewPlayer2.setText(Integer.toString(player2Points));
    Toast.makeText(this,"Player 2 has won",Toast.LENGTH_SHORT).show();
    resetBoard();

}
private void resetBoard(){
    try {
        Thread.sleep(1000);
    } catch (InterruptedException e) {
        e.printStackTrace();
    }
    for(int i=0;i<3;i++){
        for(int j=0; j<3; j++){
            buttons[i][j].setText("");
        }
    }
    roundCount =0;
}
private void draw(){
    Toast.makeText(this,"Draw",Toast.LENGTH_SHORT).show();
    resetBoard();


}

}

0 个答案:

没有答案