我正在尝试使代码工作起来涉及goroutine中的通道(在C#中类似yield的行为)
代码涉及从切片中获取可迭代矩阵,如下所示:
elements := []float64{1, 2, 3, 4}
expected := [][]float64{
{1},
{2},
{3},
{4},
{1, 2},
{1, 3},
{2, 3},
{1, 4},
{2, 4},
{3, 4},
{1, 2, 3},
{1, 2, 4},
{1, 3, 4},
{2, 3, 4},
{1, 2, 3, 4},
}
我尝试通过以下方式应用Knuth:
func Combinadic(values []float64) <-chan []float64 {
ch := make(chan []float64)
go func() {
for i := 0; i < len(values); i++ {
for value := range CombinadicK(values, i+1) {
ch <- value
}
}
close(ch)
}()
return ch
}
func CombinadicK(values []float64, k int) <-chan []float64 {
chnl := make(chan []float64)
go func() {
n := len(values)
t := k
c := make([]int, t+3)
current := make([]float64, t)
x := 0
j := 0
for j = 1; j <= t; j++ {
c[j] = j - 1
}
c[t+1] = n
c[t+2] = 0
j = t
for {
for i := 0; i < len(current); i++ {
current[i] = values[c[i+1]]
}
chnl <- current
if j > 0 {
x = j
} else {
if c[1]+1 < c[2] {
c[1]++
continue
} else {
j = 2
}
}
for {
c[j-1] = j - 2
x = c[j] + 1
if x == c[j+1] {
j++
} else {
break
}
}
c[j] = x
j--
if j >= t {
break
}
}
close(chnl)
}()
return chnl
}
似乎每行给出随机数,但是预期的结构(每行项目数)似乎还可以。
中的代码答案 0 :(得分:1)
您有一场数据竞赛。您的结果不确定。
$ go run -race racer.go
==================
WARNING: DATA RACE
Read at 0x00c00009c010 by main goroutine:
reflect.typedmemmove()
/home/peter/go/src/runtime/mbarrier.go:177 +0x0
reflect.packEface()
/home/peter/go/src/reflect/value.go:119 +0x103
reflect.valueInterface()
/home/peter/go/src/reflect/value.go:1027 +0x16f
fmt.(*pp).printValue()
/home/peter/go/src/reflect/value.go:997 +0x38f7
fmt.(*pp).printValue()
/home/peter/go/src/fmt/print.go:868 +0xec7
fmt.(*pp).printArg()
/home/peter/go/src/fmt/print.go:715 +0x2ee
fmt.(*pp).doPrintln()
/home/peter/go/src/fmt/print.go:1172 +0xad
fmt.Fprintln()
/home/peter/go/src/fmt/print.go:263 +0x65
main.main()
/home/peter/go/src/fmt/print.go:273 +0x14b
Previous write at 0x00c00009c010 by goroutine 8:
main.CombinadicK.func1()
/home/peter/racer.go:48 +0x1e6
Goroutine 8 (running) created at:
main.CombinadicK()
/home/peter/racer.go:26 +0x96
main.Combinadic.func1()
/home/peter/racer.go:12 +0xda
==================
[3]
[3]
[4]
[4]
[2 3]
[2 4]
[1 4]
[3 4]
[3 4]
[3 4]
[1 3 4]
[1 3 4]
[1 3 4]
[2 3 4]
[1 2 3 4]
Found 1 data race(s)
exit status 66
$
racer.go
:
package main
import (
"fmt"
)
func Combinadic(values []float64) <-chan []float64 {
ch := make(chan []float64)
go func() {
for i := 0; i < len(values); i++ {
for value := range CombinadicK(values, i+1) {
ch <- value
}
}
close(ch)
}()
return ch
}
func CombinadicK(values []float64, k int) <-chan []float64 {
chnl := make(chan []float64)
go func() {
n := len(values)
t := k
c := make([]int, t+3)
current := make([]float64, t)
x := 0
j := 0
for j = 1; j <= t; j++ {
c[j] = j - 1
}
c[t+1] = n
c[t+2] = 0
j = t
for {
for i := 0; i < len(current); i++ {
current[i] = values[c[i+1]]
}
chnl <- current
if j > 0 {
x = j
} else {
if c[1]+1 < c[2] {
c[1]++
continue
} else {
j = 2
}
}
for {
c[j-1] = j - 2
x = c[j] + 1
if x == c[j+1] {
j++
} else {
break
}
}
c[j] = x
j--
if j >= t {
break
}
}
close(chnl)
}()
return chnl
}
func main() {
elements := []float64{1, 2, 3, 4}
for v := range Combinadic(elements) {
fmt.Println(v)
}
}
游乐场:https://play.golang.org/p/hhQgVdqe6l1