按多列将表格数据分组

时间:2019-05-24 04:11:31

标签: perl

我有这种格式的数据

b1  1995    1
b1  2007    0.1
b2  1974    0.1
b2  1974    0.6
b2  1975    0.3

而且,我想基于第1列和第2列中的相似值对第3列中的值求和。

我写了一个代码,将其值相加,但是我不知道如何打印组值。

use strict;
use warnings;
use Data::Dumper;
my $file=shift;
open (DATA, $file);
my %score_by_year;

while ( my $line = <DATA> )
{
        my ($protein, $year, $score) = split /\s+/, $line;
        $score_by_year{$year} +=$score;
        print "$protein\t$year\t$score_by_year{$year}\n";
}
close DATA;

所以我的代码将输出显示为:

b1  1995    1
b1  2007    0.1
b2  1974    0.1
b2  1974    0.7
b2  1975    0.3

而预期的输出是这样的:

b1  1995    1
b1  2007    0.1
b2  1974    0.7
b2  1975    0.3

1 个答案:

答案 0 :(得分:1)

要保留序列,请存储它:

use strict;
use warnings;

my @sequence;
my %scores_by_year;

while (<DATA>) {
   my ($protein, $year, $score) = split;
   if (not exists $scores_by_year{$protein}{$year}) {
     push @sequence, [$protein, $year];
   }
   $scores_by_year{$protein}{$year} += $score;
}

for my $protein_year (@sequence) {
  my($protein, $year)= @$protein_year;
  print join("\t", $protein, $year, $scores_by_year{$protein}{$year}), "\n";
}
__DATA__
b1  1995    1
b1  2007    0.1
b2  1974    0.1
b2  1974    0.7
b2  1975    0.3